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Lady_Fox [76]
2 years ago
11

Which shows the domain and range of these functions? Domain: (Negative infinity, infinity) Range: (Negative infinity, infinity)

Domain: (0, infinity) Range: (Negative infinity, infinity) Domain: (Negative infinity, infinity) Range: (0, infinity).
Mathematics
1 answer:
Alex2 years ago
4 0

The domain (input values) and range (output values) of the function is, Domain: (Negative infinity, infinity), Range: (0, infinity).

<h3>What is domain and range of function?</h3>

Domain of a function is the set of all the possible input values which are valid for that function.

Range of a function is the set of all the possible output values which are valid for that function.

Given information-

The function given in the problem is,

y=f(x)\\y=h(x)\\y=g(x)\\y=k(x)

As domain of a function is the set of all the possible input values which are valid for that function. Thus the function should accept all the values for the given function.

Here in the given function the function is takes the input for all the real number form positive to the negative infinite. Thus the domain of the function is,

Domain: (-∞, ∞).

Range of a function is the set of all the possible output values which are valid for that function.

Here the output for the given function gives the positive values to the infinite. thus the range of the function is,

Range: (0, ∞).

Thus, the domain and range of the function is, domain: (Negative infinity, infinity), range: (0, infinity).

Learn more about the domain and range of the function here;

brainly.com/question/2264373

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Answer:

Range: (844.9,1333.7)

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Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1083.9 cm cubed

Standard Deviation, σ = 122.2 cm cubed

Range rule thumb:

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\text{Range} = 4\times \sigma = 4\times 122.2 = 488.8

Upper Limit:

\mu + 2\sigma = 1089.3 + 2(122.2) = 1333.7

Lower limit:

\mu - 2\sigma = 1089.3 - 2(122.2) = 844.9

Since, 1348.3 does not lie in the range (844.9,1333.7),  a brain volume of 1348.3 cm cubed can be considered significantly high.

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