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Lady_Fox [76]
2 years ago
11

Which shows the domain and range of these functions? Domain: (Negative infinity, infinity) Range: (Negative infinity, infinity)

Domain: (0, infinity) Range: (Negative infinity, infinity) Domain: (Negative infinity, infinity) Range: (0, infinity).
Mathematics
1 answer:
Alex2 years ago
4 0

The domain (input values) and range (output values) of the function is, Domain: (Negative infinity, infinity), Range: (0, infinity).

<h3>What is domain and range of function?</h3>

Domain of a function is the set of all the possible input values which are valid for that function.

Range of a function is the set of all the possible output values which are valid for that function.

Given information-

The function given in the problem is,

y=f(x)\\y=h(x)\\y=g(x)\\y=k(x)

As domain of a function is the set of all the possible input values which are valid for that function. Thus the function should accept all the values for the given function.

Here in the given function the function is takes the input for all the real number form positive to the negative infinite. Thus the domain of the function is,

Domain: (-∞, ∞).

Range of a function is the set of all the possible output values which are valid for that function.

Here the output for the given function gives the positive values to the infinite. thus the range of the function is,

Range: (0, ∞).

Thus, the domain and range of the function is, domain: (Negative infinity, infinity), range: (0, infinity).

Learn more about the domain and range of the function here;

brainly.com/question/2264373

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2 years ago
"You and your friend go to dinner and your total bill is $30. You are both part of the rewards club and have coupons. Your coupo
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3 years ago
Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.
liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

f(x) = \frac{x^2+4x+3}{x^2-x-2}

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial x^2-x-2

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

(x-2) (x + 1)

We do the same with the numerator

x^2+4x+3

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

(x+3)(x + 1)

Therefore

f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}

Note that \frac{(x+1)}{(x+1)}=1 only if x \neq -1

So since x = -1 is not included in the domain the function has a discontinuity in x = -1

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3 years ago
15 men can do a piece of work in 80 days. If 5 more men are added, how long will it take to complete same piece of work?​
tresset_1 [31]

Answer:

Step-by-step explanation:

This is an inverse proportion.

men = k / Time         So first we need to find k

k = men * Time         Substitute values

k = 15*80

k = 1200  Notice the units are man days.

Now what happens if we increase the number of men to 20? What happens to the number of days.

20 = 1200 / time          Multiply both sides by time

20*time = 1200            Now divide by 20

time = 1200/20

Answer: time = 60 days

4 0
2 years ago
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