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3 years ago

Factor each polynomial -28y^2-12y^5

Mathematics

1 answer:

artcher [175]3 years ago

8 0

Answer:

y= $-\frac{\sqrt[3]{63} }{3}$

y=0

Step-by-step explanation:

− 4 $y^{2}$ ( 3 $y^{3}$ + 7 )

-4 $y^{2}$ =0, ( 3 $y^{3}$ + 7 )=0

$y^{2}$ =0 3 $y^{3}$ =-7

y=0 $y^{3}$ = $\frac{-7}{3}$

y= $-\frac{\sqrt[3]{63} }{3}$

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Which quadratic equation fits the data in the table? (PICTURE OF TABLE ATTACHED)

Paha777 [63]

The correct quadratic equation for that set of points is:
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To check it, simply put first and last pair of points and assure the equality:
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3 years ago

Decrease the number 14.4 by 0.2 of it.

adell [148]

The result of the decrease of the number 14.4 by 0.2 of it is of 14.2.

<h3>What does it mean to decrease a number a by b of it?</h3>

The equivalent operation is the subtraction of a by b.

In this problem, we want to decrease the number 14.4 by 0.2 of it, hence the operation is:

14.4 - 0.2 = 14.2.

More can be learned about subtraction operations at brainly.com/question/4721701

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3 0

1 year ago

26. Using only digits 0, 1 and 2, this cube has a different

Art [367]

Answer:

Step-by-step explanation:

Possible largest numbers using digit 0 , 1 , 2

222

221

220

212

211

210

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7 0

3 years ago

What is the exact volume of the cone? with a 5 ft radius and a 16 ft height

andrew11 [14]

Answer:

The volume is 418.93 ft^3

Step-by-step explanation:

Here, we want to find the volume of a cone

Mathematically, we use the formula;

V = 1/3 * pi * r^2 * h

r = 5 ft

h = 16 ft

Substituting these values;

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3 0

2 years ago

2x^3-x^2+x-2 factorize

bekas [8.4K]

Answer:

$(x-1)(2x^2+x+2)$

Step-by-step explanation:

Factorize:

$f(x)=2x^3-x^2+x-2$

<u>Factor Theorem</u>

If f(a) = 0 for a polynomial then (x - a) is a factor of the polynomial f(x).

Substitute x = 1 into the function:

$\implies f(1)=2(1)^3-1^2+1-2=0$

Therefore, (x - 1) is a factor.

As the polynomial is cubic:

$\implies f(x)=(x-1)(ax^2+bx+c)$

Expanding the brackets:

$\implies f(x)=ax^3+bx^2+cx-ax^2-bx-c$

$\implies f(x)=ax^3+(b-a)x^2+(c-b)x-c$

Comparing coefficients with the original polynomial:

$\implies ax^3=2x^3 \implies a=2$

$\implies (b-a)x^2=-x^2 \implies b-2=-1 \implies b=1$

$\implies -c=-2 \implies c=2$

Therefore:

$\implies f(x)=(x-1)(2x^2+x+2)$

Cannot be factored any further.

4 0

2 years ago

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