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zimovet [89]
3 years ago
13

Determine the intercepts of the line. y = -3.2 + 12 y-intercept: X-intercept:

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0

Answer:

y-intercept=12

x-intercept= something not sure

Step-by-step explanation:

i know the first one just not the second i hope thats ok im sure someone else will know

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In a class of 30 student .(x+10) study Algebra.(10x-3) study statistics ,4 students study both Algebra and statistics,2x study o
kherson [118]

Answer:

Step-by-step explanation:

3 0
2 years ago
3×0.7= <br> And could you please do the model
otez555 [7]

Answer: 2.1, I don't really know how to show a model for this, its just that when you multiply 3 and 7 you get 21, when you do 0.7 and 3, you just put the decimal place between the 2 and 1.

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3 years ago
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos &#10;y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
Which equation has a slope of -2 and passes through the point (1,-6)?
Naily [24]

Answer:

y=-2x-4

Step-by-step explanation:

Given that,

Slope, m = -2

It passes through the point (1,-6).

We need to find the equation of line that passes throgh the given point. It can be calculated as:

y-y_1=m(x-x_1)

Put y₁ = -6, x₁ = 1 and m = -2

y-(-6)=(-2)(x-1)\\\\y+6=-2x+2\\\\y+2x+6-2=0\\\\y=-2x-4

Hence, the equation of line is y=-2x-4.

7 0
2 years ago
100pts: Why was obsidian used to make scalpels?
Margaret [11]

Answer:

Research also confirms that incisions carried out with obsidian produce narrower scars and fewer inflammatory cells. This is because on cellular level, obsidian knife cuts between cells rather than tearing it in case of a steel knife, hence, a sharper cut allows the wound to heal more easily with negligible scarring.

3 0
3 years ago
Read 2 more answers
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