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iVinArrow [24]
3 years ago
12

The solutions of x^2= 16x-28

Mathematics
2 answers:
-BARSIC- [3]3 years ago
6 0
The answer it (4,14)
STALIN [3.7K]3 years ago
5 0

Answer:

Simplifying

x2 = 16x + -28

Reorder the terms:

x2 = -28 + 16x

Solving

x2 = -28 + 16x

Solving for variable 'x'.

Reorder the terms:

28 + -16x + x2 = -28 + 16x + 28 + -16x

Reorder the terms:

28 + -16x + x2 = -28 + 28 + 16x + -16x

Combine like terms: -28 + 28 = 0

28 + -16x + x2 = 0 + 16x + -16x

28 + -16x + x2 = 16x + -16x

Combine like terms: 16x + -16x = 0

28 + -16x + x2 = 0

Factor a trinomial.

(2 + -1x)(14 + -1x) = 0

Subproblem 1

Set the factor '(2 + -1x)' equal to zero and attempt to solve:

Simplifying

2 + -1x = 0

Solving

2 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.

2 + -2 + -1x = 0 + -2

Combine like terms: 2 + -2 = 0

0 + -1x = 0 + -2

-1x = 0 + -2

Combine like terms: 0 + -2 = -2

-1x = -2

Divide each side by '-1'.

x = 2

Simplifying

x = 2

Subproblem 2

Set the factor '(14 + -1x)' equal to zero and attempt to solve:

Simplifying

14 + -1x = 0

Solving

14 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-14' to each side of the equation.

14 + -14 + -1x = 0 + -14

Combine like terms: 14 + -14 = 0

0 + -1x = 0 + -14

-1x = 0 + -14

Combine like terms: 0 + -14 = -14

-1x = -14

Divide each side by '-1'.

x = 14

Simplifying

x = 14

Solution

x = {2, 14}

Step-by-step explanation:

I type fast lol

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Answer:

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Step-by-step explanation:

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Observe that

\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}

and

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Then

\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}

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