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Hunter-Best [27]
3 years ago
13

Which expression represents ¨the product of a number and 6¨?

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
5 0

Answer:

n*6

Step-by-step explanation:

A number being n and the product meaning multiplication.

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There are five possible types of solutions to the system of nonlinear equations representing an ellipse and a circle

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You are given a problem that involves multiplying a positive number and a negative number. Which of the following are reasonable
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Luicia tried to solve the system 2x +2y =14 x-2y=-2​
Anna71 [15]

Answer:

(x, y) = (-1/4, -3/4)

Step-by-step explanation:

1. Write as a system

2x + 2y = 14x - 2y = -2

2. Eliminate one variable by adding the equations

2x + 2y = -2

14 x - 2y = -2

3. Divide both sides by 16

16x = -4

4. Substitute the value of x into the equation.

x = -1/4

5. Solve the equation

2(-1/4) + 2y = -2

6. A possible solution is

y = -3/4

7. Check the solution

(x, y) = (-1/4, -3/4)

8. Simplify the expression

2(-1/4) + 2(-3/4) = 14(1/4) - 2(-3/4) = -2

9. The ordered pair is a solution

-2 = -2 = -2

10. (x, y) = (-1/4, -3/4)

3 0
3 years ago
A 15-ft ladder rests against a vertical wall. If the top of the ladder slides down the wall at a rate of 0.33 ft/sec, how fast,
3241004551 [841]

Answer:

0.44 ft/sec.

Step-by-step explanation:

Let A is the bottom of the ladder and AB is the distance from the bottom of the wall i.e. B is the bottom of the wall. If C is the top of the ladder and BC is the height of the wall.

Now, Δ ABC is a right triangle and AC is the length of the ladder i.e. hypotenuse.

Now, AC² = AB² + BC² {From Pythagoras Theorem}

Now, differentiating both sides with respect to time t, we get

0 = 2 \times (AB) \times \frac{d(AB)}{dt} +  2 \times (BC) \times \frac{d(BC)}{dt}

⇒  \frac{d(AB)}{dt} = - \frac{BC}{AB} \times  \frac{d(BC)}{dt}

Now, given that \frac{d(BC)}{dt} = - 0.33 feet/sec.

Hence, \frac{d(AB)}{dt} = - \frac{BC}{AB} \times  (- 0.33) ......... (1)

Now, given that AB = 9 ft. and AC = 15 ft.

So, 15² = 9² + BC²  

⇒ BC² = 144

⇒ BC = 12 feet.

Now, from equation (1), we get

\frac{d(AB)}{dt} = - \frac{12}{9} \times  (- 0.33) = 0.44

Therefore, the bottom of the ladder is sliding away from the wall at the rate of 0.44 ft/sec. (Answer)

3 0
3 years ago
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