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sergeinik [125]
3 years ago
7

Which expression is equal to p + (q + r)?

Mathematics
2 answers:
Verdich [7]3 years ago
5 0
The answer is letter B.
ANTONII [103]3 years ago
4 0
Your answer is B. (p + q) + r
This is because when doing addition, the order of the addition doesn't matter, as in both instances all of the terms are getting added together. I hope this helps!
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John bought 3 pineapples and 2 watermelons for $8.50. Sue bought 2 pineapples and 4 watermelons for $13.00. Write and show a sys
AleksAgata [21]
As per your question, total cost of watermelon should end with either 5(for odd quantity) or 0(for even quantity).

If the quantity of watermelon is odd, then the total cost value of pineapple should end with 3 and this is not possible when the cost of pineapple is ₹7.

So let's come to conclusion that the count(quantity) of watermelon should be any one of 0, 2, 4, 6.

If count of watermelon is 6: It will cost ₹30 and for remaining ₹8, we can buy 1 pineapple but still ₹1 will not be utilised. So 1 pineapple is not possible

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If count of watermelon is 2: It will cost ₹10 and for remaining ₹28, we can buy 4 pineapple with all amount being utilised. We can buy 4 pineapple along with with 2 watermelon for ₹38.

If count of watermelon is 0: It will cost you ₹0 and for remaining ₹38, we can buy 5 pineapple with ₹3 being not utilised. So 5 pineapple is also not possible.

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5 0
3 years ago
Solve. You must factor first.<br><br> 5x^2+ 17x+ 14=0<br> Please show work
Soloha48 [4]

Answer:

the answer is <em><u>X</u></em><em><u>=</u></em><em><u>-</u></em><em><u>3</u></em>

<em><u>1</u></em><em><u>)</u></em><em><u> </u></em><u>5</u><em><u>x</u></em><u>^</u><u>2</u><u>+</u><u>1</u><u>7</u><em><u>x</u></em><u>+</u><u>1</u><u>4</u><u>=</u><u>0</u>

<u>2</u><u>)</u><u>5</u><em><u>x</u></em><u>^</u><u>2</u><u>+</u><u>1</u><u>7</u><em><u>x</u></em><em><u>=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>4</u></em><em><u>+</u></em><em><u>0</u></em>

<em><u>3</u></em><em><u>)</u></em><em><u>2</u></em><em><u>5</u></em><em><u>x</u></em><em><u>+</u></em><em><u>1</u></em><em><u>7</u></em><em><u>x</u></em><em><u>=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>4</u></em>

<em><u>4</u></em><em><u>)</u></em><em><u>4</u></em><em><u>2</u></em><em><u>x</u></em><em><u>=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>4</u></em>

<em><u>5</u></em><em><u>)</u></em><em><u>4</u></em><em><u>2</u></em><em><u>x</u></em><em><u>/</u></em><em><u>-</u></em><em><u>1</u></em><em><u>4</u></em>

<em><u>6</u></em><em><u>)</u></em><em><u>x</u></em><em><u>=</u></em><em><u>-</u></em><em><u>3</u></em>

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3 years ago
When will you need hexadecimals in life?
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Write down the decimal equivalent to;
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A) 25% = 25/100 = 0.25

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e) 0.15% = 0.15/100 = 0.0015
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3 years ago
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