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astraxan [27]
3 years ago
7

You have $24 to spend on four raffle tickets. After buying you ended up with $11. How much did each raffle ticket cost (4.) PLEA

SE HELP MEEEE I WILL MAKE YOU BRAINIEST
!

Mathematics
1 answer:
romanna [79]3 years ago
6 0

Answer:

each ticket cost $3.25

Step-by-step explanation:

24-11=13

13÷4=3.25

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If 60 blimps each had 70 people on board,how many people would be riding on the blimp
Romashka [77]
4,200 people would be on all the blimps
4 0
3 years ago
Leo has a total of 45 cents. He has some dimes and pennies. How many combinations of dimes and pennies could leo have?
Lynna [10]
The list of possible combination of Leo's 45c is below. He could have 0 dimes and 45 pennies, 4 dimes and 5 pennies, 2 dime and 25 pennies, 1 dimes and 35 pennies, 3 dimes and 15 pennies.Leo would have 5 different combination and if you want to have it in table just put the numbers in the table with dimes on one side and pennies on the other.
5 0
3 years ago
The equation of line CD is y = −2x − 2. What is the equation of a line parallel to line CD in slope-intercept form that contains
aniked [119]

Answer:

\[y=-2x+13\]

Step-by-step explanation:

Equation of the line CD is given as \[y=-2x-2\]

Slope of the line CD = -2

Slope of the line parallel to CD = -2

Equation of the line parallel to CD is given by \[y=mx+c\]

\[y=-2x+c\]

But this line passes through (4,5)

Substituting the values in the equation:

\[5=-2*(4)+c\]

=> \[c=5+8=13\]

So the overall equation of the parallel line is given by \[y=-2x+13\]

6 0
3 years ago
A baseball training clinic takes out a loan to build in reception area the loan is for $28,500 at 4.25% for five years how much
myrzilka [38]
The answer would be 1211.25 because 28500 x 0.0425 is equal to that. (don't trust this answer).
5 0
3 years ago
Read 2 more answers
A lead ball weighs 326 grams. Find the radius of the ball to the nearest tenth of a<br> centimeter.
rjkz [21]

Answer:

1.9cm

Step-by-step explanation:

The density d of a material is related to its mass m and volume V as follows;

d = \frac{m}{V}             ------------------(i)

The material in question here is the lead ball.

Now, from known experiment;

the density of lead is <em>11.34g/cm³</em>

From the question, the weight/mass of the lead ball is <em>326g</em>

Substitute these values into equation (i) as follows;

11.34 = \frac{326}{V}

V = \frac{326}{11.34}

V = 28.75cm³

Now, since the ball is of course spherical, we can get the radius by using the following relation from the volume of a sphere;

V = \frac{4}{3} \pi r^3          [V = volume, r = radius]

V = 28.75cm³

=> 28.75 = \frac{4}{3} \pi r^3

=> 3 x 28.75 = 4 π r³

=> 86.25 = 4 π r³

=> 21.5625 = π r³      [Take π = 3.142]

=> 21.5625 = (3.142) r³      [divide both sides by 3.142]

=> 6.86 = r³              [Take the cube root of both sides]

=> ∛6.86 = ∛r³

=> 1.90 = r

Therefore, the radius is 1.9cm to the nearest tenth

5 0
3 years ago
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