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2 years ago

PLEASE HELP! I have a picture of the question below :)

Mathematics

1 answer:

Charra [1.4K]2 years ago

6 0

3. ∠1+∠2=180° and ∠2+∠3=180°

4. they are supplementary

5. ∠1+∠2=180°=∠2+∠3

6. ∠1+∠2=180°=∠2+∠3

∠2 are same in both side so ∠1=180°-∠2 =∠3=180°-∠2

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Can someone help me with this please?

Vladimir79 [104]

With what? Don’t see anything

6 0

2 years ago

A new gas- and electric-powered hybrid car has recently hit the market. The distance traveled on 1 gallon of fuel is normally di

Doss [256]

Answer:

a) P [ Z > 70 ] = 0.1075 or 10.75 %

b) P [ Z < 60 ] = 0.1038 or 10.38 %

c) P [ 55 ≤ Z ≤ 70 ] = 0.8882 or 88.82 %

Step-by-step explanation:

Normal Distribution μ = 65 and σ = 4

a) The probability of the car travels more than 70 miles per gallon is:

P [ Z > 70 ] = (Z-μ) ÷ σ ⇒ P [ Z > 70 ] = (70-65) ÷4 P [ Z > 70 ] = 1.25

the point 1.25 corresponds at values, from left tail up to 70 so we must go and look for the area for the point 1.24 which is 0.8925. Then we have the area or probability of all cars traveling up to 70 miles therefore we have to subtract 1 -0,8925

P [ Z > 70 ] = 0.1075 or 10.75 %

b)The probability of the car travels less than 60 miles per gallon is:

P [ Z < 60 ] = ( 60 - μ ) ÷ σ ⇒ P [ Z < 60 ] = (60-65)÷ 4 P [ Z < 60 ] = -1.25

Again -1.25 corresponds to 60 miles per gallon threfore we move to the left and find for point -1.26 which area is 0.1038 so

P [ Z < 60 ] = 0.1038 10.38 %

c) P [ 55 ≤ Z ≤ 70]

For point Z = 70 or 1.25 (case a above) P [ Z ≤ 70] = (70-65)÷4

P [ Z ≤ 70] = 1.25

In this case we got the whole area from the left tail up to 1.25

P [ Z ≤ 70] = 0.8944 (includes the area of the point from the left tail up to the point assocciated to 55 miles and for that reason we have to subtract that area)

P [ Z ≥ 55 ] = (55-65) ÷ 4 P [ Z ≥ 55 ] = -2.5 and the area is 0.0062

So P [ 55 ≤ Z ≤ 70 ] = 0.8944 - 0.0062 = 0.8882

8 0

2 years ago

100 BRAINLY POINTS

Troyanec [42]

Answer:

Given

f(x)=18,000(.88)^x

We need to find the value of x when f(x) <2000

2000 = 18000(0.88)^x

0.88^x 2000/18000

0.88^x 1/9

• x = log (1/9) / log (0.88)

• x= 17 (rounded down)

After 17 years or during year 18 the car value will drop below $2000

3 0

2 years ago

The distance of planet Mercury from the Sun is approximately 5.8 ⋅ 10^7 kilometers, and the distance of Earth from the Sun is 1.

egoroff_w [7]

Answer:

The answer is 9.2 * 10^7

Step-by-step explanation:

(1.5*10^8)-(5.8*10^7)=92,000,000

92,000,000= 9.2* 10^7

6 0

1 year ago

Read 2 more answers

What is the best approximation for the perimeter of polygon ABCDE? A. 11.0 units B. 17.0 units C. 24.3 units D. 22.1 units

erastovalidia [21]

TheThe best approximation for the perimeter of polygon ABCDE is: C. 24.3 units.

<h3>Perimeter of polygon</h3>

Coordinate:

A=(-2,3)

B=(0,6)

C=(5,4)

D=(4,-1)

E=(-1,-2)

Distance AB=√(0+2)²+(6-3)²

Distance AB=√4+9

Distance AB=√13

Distance BC=√(5-0)²+(4-6)²

Distance BC=√25+4

Distance BC=√29

Distance CD=√(4-5)²+(-1-4)²

Distance CD=√1+25

Distance CD=√26

Distance DE=√(-1-4)²+(-2+1)²

Distance DE=√25+1

Distance DE=√26

Distance EA=√(-2+1)²+(3+2)²

Distance EA=√1+25

Distance EA=√26

Perimeter of pathogen ABCDE

=AB+BC+CD+DE+EA

=√13+√29+√26+√26+√26

=√13+√29+3√26

=24.2877 units
= 24.3 units (Approximately)

Therefore the correct option is C.

Learn more about Perimeter of polygon here:brainly.com/question/3310006

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7 0

1 year ago

Read 2 more answers