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Citrus2011 [14]
3 years ago
11

if 5000000 invested at 4% interest compounded continuously how much will the investment be worth in 30 years

Mathematics
2 answers:
umka21 [38]3 years ago
8 0
For this you use A=Pe^(rt)
A=furutre amount
P=present amount
e=natural base
r=rate in decimal
t=times in years

A=?
P=5000000
r=0.04
t=30

A=5,000,000e^(0.04*30)
A=5,000,000e^(1.2)
A=16600584.613683
Anna35 [415]3 years ago
6 0
The required formula is:
A=Pe^{rt}
where A is the amount after t years, e is the exponential number and r is the annual interest rate expressed as a decimal:
Plugging in the given values into the formula:
A=5000000\times e^{(0.04\times 30)}=16,600,584.61\ currency\ units
You might be interested in
Patrick ate 2/3 of a fruit bar write an equivalent fraction for the amount of fruit bar Patrick ate
Marina86 [1]
To get an equivalent fraction, multiply the fraction by a whole number. For example, you can do 2/3 times 2 to both sides which is 4/6.
5 0
3 years ago
If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
2 years ago
[MATH] I need help on all of them! Please and thank you <33
REY [17]

Answer:

2) 45

3) 25

4) 50%

5) 33.3%

6) 17.6

7) 500

8) 35%

9) 60

10) 87.5%

11) 2.64

12) 25%

13) 5.7

14) 85%

16) 75%

Step-by-step explanation:

2) 9 = 20% of x

9 * 5 = 45

3) 8% of x = 2

12.5 * 2 = 25

4) 39 = x(78)

39/78 = 1/2 = 50%

5) x(36) = 12

12/36 = 1/3 = 33.3...%

6) x = 0.8(22)

22/10 = 2.2

2.2* 8 = 16 + 1.6 = 17.6

7) 55 = 0.11(x)

55/11 = 5

5 * 100 = 500

8) 7/20 = 35/100 = 35%

9) 27 = 0.45(x)

27/45 = 3/5

3/5 * 100 = 300/5 = 60

10) . 49/56 = 7/8 = 0.875 = 87.5%

11) 6/100 = 0.06

0.06 * 44 = 2.64

12) 48/192 = 6/24 = 1/4 = 25%

13) 95/100 = 0.95

0.95 * 6 = 5.40 + 0.3 = 5.7

14) 68/80 = 34/40 = 17/20 = 85%

16) 108/144 = 9/12 = 0.75 = 75%

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

3 0
3 years ago
Please answer it correctly and I'll mark it​
kirza4 [7]

Answer:

Step-by-step explanation:

1) a very poor question indeed. It has at least two possible solutions

c = 3x + 2                                     or     c = 3(x + 2)

when x = 2

c = 3(2) + 2 = 8                           or      c = 3(2 + 2) = 12                  

when x = 5

c = 3(5) + 2 = 17                          or       c = 3(5 + 2) = 21

2)

y = x + 2

when x = 2

y = 2 + 2 = 4

when x = 5

y = 5 + 2 = 7

8 0
2 years ago
What kind of triangle?
Step2247 [10]

Answer:

I think it's an obtuse scalene.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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