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3 years ago

If a= 3 and b= 5, find (a + b) O 8/5 3/8 5/8

Mathematics

2 answers:

PIT_PIT [208]3 years ago

6 0

Answer:

5/8

Step-by-step explanation:

have a good day!

hichkok12 [17]3 years ago

3 0

answer: it would be 5/8

Step-by-step explanation:

5/(3+5)=5/8

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The fitted regression is Sales = 832 − 28.2 Price. (a-1) If Price = 1, what is the prediction for Sales? (Round your answer to 1

almond37 [142]

Answer:

Part (a-1): The prediction for Sales is 803.8.

Part (a-2): The correct option is: An increase in price decreases sales.

Part (B): The prediction for sales is 211.66

Part (C): The intercept is meaningful as sales will be maximized when price is zero.

Step-by-step explanation:

Consider the provided regression:

Sales = 832 − 28.2 Price

(a-1) If Price = 1, what is the prediction for Sales?

Substitute Price = 1 in above regression.

Sales = 832 − 28.2 (1) = 803.8

Hence, the prediction for Sales is 803.8.

Sales (a-2) Choose the correct statement.

Here we can observe that as we increase the price, sales decrease.

Thus, the correct option is: An increase in price decreases sales.

(b) If Price = 22, what is the prediction for Sales?

Substitute Price = 22 in above regression.

Sales = 832 − 28.2 (22)

Sales = 832 − 620.4

Sales = 211.66

Hence, the prediction for sales is 211.66

Sales (c) Choose the right option.

As we increase the price, sales decrease that means the sales will be maximum if the price is 0.

The intercept is meaningful as sales will be maximized when price is zero.

3 0

3 years ago

Find the distance between points M(-1,-10) and (-12,-3). round to the nearest tenth

Kitty [74]

The formula of the distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points (-1, -10) and (-12, -3). Substitute:

$d=\sqrt{(-12-(-1))^2+(-3-(-10))^2}=\sqrt{(-11)^2+7^2}=\sqrt{121+49}=\sqrt{170}$

$\sqrt{170}\approx13.04$

Answer: d ≈ 13.0

4 0

3 years ago

Solve the equation. –x 8 3x = x – 6 x = –18 x = –14 x = 2 x = 4

LenKa [72]

The value of the variable x in the equation –x + 8 + 3x = x – 6 is - 14.

<h3>How to find variable in an equation?</h3>

The variables of an equation can be found as follows:

–x + 8 + 3x = x – 6

The variable in the equation is x.

Therefore,

–x + 8 + 3x = x – 6

combine like terms on the left side

-x + 3x + 8 = x - 6

2x + 8 = x - 6

subtract x form both sides of the equation

2x - x + 8 = - 6

x + 8 = -6

subtract 8 from both sides

x = -6 - 8

x = - 14

learn more on equation here: brainly.com/question/1347990

#SPJ4

3 0

2 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

<em>On integration , we get</em>

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$

After simplification and cancellation we get

= $\frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6$

on calculation , we get

= $\frac{124,416}{5} + \frac{864}{3} + 180$

On L.C.M 15

= $\frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}$

= 25 351.2 units²

<u><em>Conclusion</em></u>:-

<em>The area of the region between the graph of the given function and the x-axis = 25,351 units²</em>

6 0

3 years ago

In a population of 1000 snails, tests of snail color genes show that 160 snails are AA, 480 are Aa and 360 are aa. What is the f

Kipish [7]

Answer:

Option C.

Step-by-step explanation:

Total population = 1000 snails

AA = 160 snails

Aa = 480 snails

aa = 360 snails

Frequency of each type.

$AA=\dfrac{160}{1000}=0.16$

$Aa=\dfrac{480}{1000}=0.48$

$aa=\dfrac{360}{1000}=0.36$

Now, we get

$A^2=0.16\Rightarrow A=\sqrt{0.16}=0.4$

he frequency of the A allele in this population is 0.4.

Therefore, the correct option is C.

3 0

3 years ago