Missing question: How many executives should be surveyed?
Solution:
Mean = 13 hours
SD = 3 hours
Confidence level = 95%
Mean viewing time within a quarter of an hour = 0.25 = 1.96*3/sqrt (N)
Where N = Sample population
N = {(1.96*3)/0.25}^2 = 553.19 ≈ 554
Therefore, 554 executives should be surveyed to yield such results.
Answer:
non mutually exclusive event
Step-by-step explanation:
im not sure on this tho
Answer:
12
Step-by-step explanation:
Average of A and B is 6
(A+B) /2 = 6
Multiply each side by 2
A+B = 12
average of X, Y, and Z is 16
(X+Y+Z)/3 = 16
Multiply each side by 3
(X+Y+Z) = 48
To find the average of all of them
(A+B+X+Y+Z)/5
replace A+B with 12 and X+Y+Z with 48
(12+48)/5
60/5 = 12