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2 years ago

Find missing part of the until rate 40students/5groups = ??/??

Mathematics

1 answer:

padilas [110]2 years ago

8 0

Answer:

8 students per group

8students/1group

hope that helps uhh!!!

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2.6.PS-

mojhsa [17]

Answer:

Step-by-step explanation:

5 bags= $12.50

1= ?

$12.50*1= 12.50

$12.50/5= $2.5

$2.5*5=$12.5

$2.5*3= $7.5

3 bags= $7.5

8 0

2 years ago

Please help me please

aleksandrvk [35]

Answer:

66.5

Step-by-step explanation:

Let θ represent ∠MLK

Arc length (s) = radius (r) · θ (theta must be in radians)

Step-by-step explanation:

4 0

3 years ago

A rectangular football field is 64 meters wide and 100 maters long. A player runs from one corner of the field in a diagonal lin

Dimas [21]

Answer:

119 or 118.726577

Step-by-step explanation:

We should use the Pythagorean Theorem to solve this problem.

a^2+ b^2=c^2

64^2+100^2=c^2

4096+10000=14096

c^2=14096

c=\sqrt{14096}14096

And the root of 14096 is 118.726577.

So the Answer is About 119 meters, or 118.726577

hope this helps!

3 0

2 years ago

The U.S. Census Bureau conducts a study to determine the time needed to complete the short form. The Bureau surveys 200 people.

NISA [10]

Answer:

$8.2-2.58\frac{2.2}{\sqrt{18}}=6.86$

$8.2+2.58\frac{2.2}{\sqrt{18}}=9.54$

So on this case the 90% confidence interval would be given by (6.86;9.54) And the error is given by:

$ME= 2.58\frac{2.2}{\sqrt{18}} =1.338$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=8.2$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=2.2$ represent the population standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$