9514 1404 393
Answer:
20 minutes
Step-by-step explanation:
The trains are separating at the rate of 80 +70 = 150 km/hour. The time required to be 50 km apart is then ...
time = distance/speed = (50 km)/(150 km/h) = 1/3 h = 20 minutes
im not sure this is right
g'(x) = 6b(-5x + 1)^5 (-5)
g'(x) = -30b(-5x +1)^5
g''(x) = -30b(5)(-5x + 1)^4 (-5)
g''(x) = 750b (-5x +1)^4
g(x) = b(−5x + 1)6 − a
when
g(-x) = b(5x +1)6 - a
g'(x) = -30b(-5x +1)^5 = 0
-5x +1 = 0
x = 15
Answer:
parallel= 
x-intercept(s): (
6
,
0
)
y-intercept(s): (
0
,
4
)
Hope this helps :)
If we draw a diagonal which will also be a transversal DB, then we get ∠ADB is congruent to ∠CBD by Alternate interior angles.
It will be the first option.
Step-by-step explanation:
can I have actual options I can't figure it out with invalid options
