Answer: a) Mean = 5, Median = 5
b) Mean = 15, Median = 5
c) Due to presence of outlier i.e. 99.
Step-by-step explanation:
Since we have given that
1,2,3,4,5,6,7,8,9
Here, n = 9 which is odd
So, Mean would be
Median = 
If 9 is replaced by 99,
1,2,3,4,5,6,7,8,99
So, mean would be
Median would be same as before i.e. 5
The mean is neither central nor typical for the data due to outlier i.e. 99
Hence, a) Mean = 5, Median = 5
b) Mean = 15, Median = 5
c) Due to presence of outlier i.e. 99.
Y= 26 & x=35 hope I did it on time!
Answer:
5
Step-by-step explanation:
We know that a^2+b^2=c^2 from the Pythagorean theorem where a and b are the legs and c is the hypotenuse
4^2+3^2 = c^2
16+9 = c^2
25 = c^2
Taking the square root of each side
sqrt(25) = sqrt(c^2)
5 =c
Find s8 for the following geometric sequence: 3, –6, 12,
–24. = –255
Answer: 24, 33
2.5, 4.75
9.5, 11.75
<u>Step-by-step explanation:</u>
It is given that the PERIMETER is BETWEEN 24 and 33
--> 24 < P < 33
Graph: O------------------O
24 33
Perimeter = 2w + 2L
It is given that L = w + 7
Substitute P with 2w + 2L and substitute L with w + 7
24 < 2w + 2(w + 7) < 33
24 < 2w + 2w + 14 < 33
10 < 4w < 19
--> 2.5 < w < 4.75
Graph: O--------------------------O
2.5 4.75
Since L = w + 7, then w = L - 7
Substitute P with 2w + 2L and substitute w with L - 7
24 < 2(L - 7) + 2L < 33
24 < 2L + 2L - 14 < 33
38 < 4L < 47
--> 9.5 < L < 11.75
Graph: O------------------------O
9.5 11.75
<em>NOTE: Make sure you use OPEN dots on the graphs.</em>
