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Bezzdna [24]
2 years ago
7

What is p - 5, for p = 19 in Algebraic Expressions 14 7 44 79

Mathematics
2 answers:
Liono4ka [1.6K]2 years ago
4 0

Answer:

\large\boxed{\boxed{\underline{\underline{\maltese{\pink{\pmb{\sf{\: Solution \rightarrow \: p = 14 }}}}}}}}

Step-by-step explanation:

We've the algebraic expression \twoheadrightarrow p - 5.

Here, we need to substitute the value of 'p' as 19 & solve the equation.

So,

\mathfrak{p - 5}\\\\\\\Longrightarrow\mathfrak{If \: \:  p = 19}\\\\\\\mathfrak{p - 5}\\\mathfrak{= (19) - 5} \\\mathfrak{= 19 - 5}\\\boxed{\mathfrak{=14}}

  • So, the value of p is <u>14.</u>

<u>__________</u>

Hope it helps!

\mathfrak{Lucazz}

Dimas [21]2 years ago
3 0

Answer:

p - 5 = 14 for p = 19

Step-by-step explanation:

Hi there!

p - 5

We're given that p = 19. Replace p with 19:

= 19 - 5

= 14

I hope this helps!

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B = -1


Hope this helps :)
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Find all solutions of the system of equations algebraicllally. Write your solutions as coordinate points Y=3x^2- 2x-1 2x+y=11
zloy xaker [14]

Answer:

(- 2, 15 ) and (2, 7 )

Step-by-step explanation:

Given the 2 equations

y = 3x² - 2x - 1 → (1)

2x + y = 11 → (2) ← subtract 2x from both sides

y = 11 - 2x → (3)

Substitute y = 3x² - 2x - 1 into (3)

3x² - 2x - 1 = 11 - 2x ( subtract 11 - 2x from both sides )

3x² - 12 = 0 ( add 12 to both sides )

3x² = 12 ( divide both sides by 3 )

x² = 4 ( take the square root of both sides )

x = ± \sqrt{4} = ± 2

Substitute these values into (3) for corresponding values of y

x = - 2 : y = 11 - 2(- 2) = 11 + 4 = 15 ⇒ (- 2, 15 )

x = 2 : y = 11 - 2(2) = 11 - 4 = 7 ⇒ (2, 7 )

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3 years ago
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