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Bezzdna [24]
2 years ago
7

What is p - 5, for p = 19 in Algebraic Expressions 14 7 44 79

Mathematics
2 answers:
Liono4ka [1.6K]2 years ago
4 0

Answer:

\large\boxed{\boxed{\underline{\underline{\maltese{\pink{\pmb{\sf{\: Solution \rightarrow \: p = 14 }}}}}}}}

Step-by-step explanation:

We've the algebraic expression \twoheadrightarrow p - 5.

Here, we need to substitute the value of 'p' as 19 & solve the equation.

So,

\mathfrak{p - 5}\\\\\\\Longrightarrow\mathfrak{If \: \:  p = 19}\\\\\\\mathfrak{p - 5}\\\mathfrak{= (19) - 5} \\\mathfrak{= 19 - 5}\\\boxed{\mathfrak{=14}}

  • So, the value of p is <u>14.</u>

<u>__________</u>

Hope it helps!

\mathfrak{Lucazz}

Dimas [21]2 years ago
3 0

Answer:

p - 5 = 14 for p = 19

Step-by-step explanation:

Hi there!

p - 5

We're given that p = 19. Replace p with 19:

= 19 - 5

= 14

I hope this helps!

You might be interested in
Ibuki factored 12x^7as (4x^3)(3x^4)
Marina86 [1]

Answer:

Both are correct.

Step-by-step explanation:

The key understanding here is that you can factor a monomial in many different ways!

To check if any of the factorizations is correct, we can multiply the factors and see if their product is really 12x^712x

7

12, x, start superscript, 7, end superscript.

Hint #22 / 4

\begin{aligned} (\blueD{4}\maroonD{x^3})(\blueD{3}\maroonD{x^4})&=(\blueD{4})(\blueD{3})(\maroonD{x^3})(\maroonD{x^4}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}

(4x

3

)(3x

4

)

​

 

=(4)(3)(x

3

)(x

4

)

=12x

7

​

So Ibuki is correct!

Hint #33 / 4

\begin{aligned} (\blueD{2}\maroonD{x^6})(\blueD{6}\maroonD{x})&=(\blueD{2})(\blueD{6})(\maroonD{x^6})(\maroonD{x}) \\\\ &=\blueD{12}\maroonD{x^7} \end{aligned}

(2x

6

)(6x)

​

 

=(2)(6)(x

6

)(x)

=12x

7

​

So Melodie is also correct!

Both Ibuki and Melodie are correct.

8 0
3 years ago
For what values of x does 25 Superscript x Baseline = 5 Superscript x squared minus 3?
umka2103 [35]

For this case we have the following equation:

25^{x} = 5^{ x^2-3}

Rewriting we have:

5^{2 (x)} = 5^{ x^ 2-3}\\5^{ 2x} = 5^{ x^ 2-3}

For expressions to be equal, exponents must be equal. So:

2x = x ^ 2-3\\x ^ 2-2x-3 = 0

To factor, we look for two numbers that, when multiplied, result in -3 and when added, result in -2. These numbers are -3 and 1.

(x-3) (x + 1) = 0

Thus, the roots are:

x_ {1} = 3\\x_ {2} = - 1

Answer:

x_ {1} = 3\\x_ {2} = - 1

8 0
3 years ago
What is the explicit formula for this sequence?
SVEN [57.7K]

Answer:

The correct answer is b.)

Step-by-step explanation:

Given:

Sequence  -7, -4, -1, 2, 5.......  => a₁ = -7, a₂ = -4, a₃ = -1, a₄ = 2 and a₅ = 5

We conclude that this sequence is arithmetic series.

First we must find difference d:

d = a₂ - a₁ = a₃ - a₂ = -4 - (-7) = -1 - (-4) = -4 + 7 = -1 + 4 = 3

d = 3

The formula for n-th term of the arithmetic series is:

aₙ = a₁ + (n-1) d

aₙ = -7 + (n-1) 3

God with you!!!

4 0
3 years ago
Jim had 5/7 of a pound of candy. she ate 1 3/4 of that candy. how many pounds of candy did he eat?
harkovskaia [24]
What she ate is
(13/4)×(5/7)
65/28 pounfs of candy
5 0
3 years ago
What is the answer to this <br> 26060/4
Paraphin [41]
26060 divided by 4 is <span>6515 :)
<em>
</em><em>Don't forget to rate this answer the Brainliest!</em>

</span>
5 0
3 years ago
Read 2 more answers
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