3^3 = 27
5^2 = 25
27 - 25 = 2
integral of 2 = 2x
(2x) evaluated from -2 to 0
= (0) - (2(-2)) = -(-4) = 4
If you did not make any mistakes in typing your question
the answer would be 4
![(\sqrt[5]{x^{7}})^{3}=(x^{\frac{7}{5}})^{3}=x^{\frac{7\cdot3}{5}}=x^{\frac{21}{5}}](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7Bx%5E%7B7%7D%7D%29%5E%7B3%7D%3D%28x%5E%7B%5Cfrac%7B7%7D%7B5%7D%7D%29%5E%7B3%7D%3Dx%5E%7B%5Cfrac%7B7%5Ccdot3%7D%7B5%7D%7D%3Dx%5E%7B%5Cfrac%7B21%7D%7B5%7D%7D)
The root is equivalent to a fractional power with that number as the denominator. Otherwise, the rules of exponents apply.
Answer:
<h2><em><u>
11.2 - B to C</u></em></h2><h2><em><u>
12 - B to A</u></em></h2><h2><em><u>
8.8 - A to C</u></em></h2>
You have to multiply all the sides by 4.
B to C = 2.8*4
2.8 * 4 = 11.2
B to A = 3*4
3*4 = 12
A to C = 2.2*4
2.2*4 = 8.8
Hope this helped!
