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N76 [4]
2 years ago
9

Select the correct answer. What is the value of x in the triangle?

Mathematics
1 answer:
maxonik [38]2 years ago
4 0

Answer:

see below

Step-by-step explanation:

attached

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What is 4(x-7)=2(x+3)?
hram777 [196]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

4(x−7)=2(x+3)

Simplify both sides of the equation.

4(x−7)=2(x+3)

4x+−28=2x+6

4x−28=2x+6

Subtract 2x from both sides.

4x−28−2x=2x+6−2x

x−28=6

Add 28 to both sides.

2x−28+28=6+28

2x=34

Divide both sides by 2.

2x/2  =  34/2

x = 17

5 0
3 years ago
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See the attached image for what the synthetic division table would look like. The cell highlighted in yellow is the remainder.

Final Answer: Choice D) 4

8 0
3 years ago
A teacher keeps track of the number of students that participate at least three times in an optional study session each year. He
Anastasy [175]

Answer:

It is not C got it wrong.

Step-by-step explanation:

6 0
3 years ago
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Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
3 years ago
How too solve (2x-3y)(4x-y) by multiplying polynomials by polynomials
Alex777 [14]
(2x-3y) (4x-y)
Multiply the polynomials using distributive property.
(a+b)(c+d) = ac+ad + bc + bd
(2x-3y) (4x-y) = (2x) (4x) + (2x)(-y) + (-3y)(4x) + (-3y)(-y)
Apply plus/minus rule.
-(-a)=a and -(a)=-a
we get
=8x²-2xy-12xy+3y²
Add like terms
=8x²-14xy+3y²

Answer: 8x² - 14xy + 3y²
4 0
3 years ago
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