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Harman [31]
3 years ago
11

Exercise 8.12 introduces data on the average monthly temperature during the month babies rst try to crawl (about 6 months after

birth) and the average rst crawling age for babies born in a given month. A scatterplot of these two variables reveals a potential outlying month when the average temperature is about 53F and average crawling age is about 28.5 weeks. Does this point have high leverage
Mathematics
1 answer:
Afina-wow [57]3 years ago
5 0

Answer:

The point has a high leverage

Step-by-step explanation:

The point has a high leverage as it would act as an infinitesimal point that will have a very huge/drastic  impact on the fit of the model, and this impact can be seen in such ways as listed below :

  • Smaller coefficient of determination
  • Higher sum of squares error

removing this point will eliminate these drastic impact and make the correlation to be better.

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kykrilka [37]

Answer:

y=1 + \frac{4x}{5}

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7 0
3 years ago
Evaluate C(44,21) use scientific notation, round to 3 decimal places as needed.
STALIN [3.7K]
C(44,21)=\dfrac{44!}{21!23!}=\dfrac{24\cdot25\cdot\ldots\cdot43\cdot44}{2\cdot3\cdot\ldots\cdot 20\cdot21}=2,012,616,400,080\\&#10;\approx2.013\cdot10^{12}
6 0
4 years ago
In 2012, the population of a small town was 3560. The population is decreasing at a rat of 1.7% per year. How can you rewrite an
RSB [31]
In 2012, the population of a small town was 3,560. The population is decreasing at a rate of 1.7% per year. How can you rewrite an exponential growth ...
6 0
3 years ago
What is the solution for 2t &lt;5
Luba_88 [7]
Divide 2 from both sides
t < 5/2
Hope this helps!
6 0
3 years ago
Read 2 more answers
A rectangle is 20 meters long and 20 meters wide. If the length is increased by 10% and the width is decreased by 10%, what is t
Solnce55 [7]

Consider that the initial length and width of the rectangle are given as,

\begin{gathered} l=20 \\ b=20 \end{gathered}

After the length is increased by 10%, the new length (L) of the rectangle is calculated as,

\begin{gathered} L=(1+\frac{10}{100})\cdot l \\ L=(\frac{110}{100})\cdot20 \\ L=22 \end{gathered}

After the width is decreased by 10%, the new width (B) of the rectangle is calculated as,

\begin{gathered} B=(1-\frac{10}{100})\cdot b \\ B=(\frac{90}{100})\cdot20 \\ B=18 \end{gathered}

Then the area (A) of the new rectangle is calculated as,

\begin{gathered} A=L\times B \\ A=22\times18 \\ A=396 \end{gathered}

Thus, the new area of the rectangle is 396 square meters.

7 0
1 year ago
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