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Scorpion4ik [409]
3 years ago
14

58:37

Mathematics
2 answers:
Sophie [7]3 years ago
6 0

To get the simplified form of the given equation. Let's simplify and find the answer!

\sf⟾  \: \red{(6 ^{  - 2}  \times 6 ^{5} )^{ - 3} }

Calculate the product using rule of exponent i.e. \boxed{ \tt \: a ^{m}  \times  {a}^{n} =  {a}^{m + n}  }

\sf⟾ \:  \orange{( {6}^{ - 2 + 5}) ^{ - 3}  }

Calculate the sum

\sf⟾ \:  \green{(6^{3}) ^{ - 3}  }

Use the rule of exponent to Simplify the power i.e. \boxed{ \tt \: ( {a}^{m} )^{n} =  {a}^{m \times n}  }

\sf⟾ \: \blue{ {6}^{ 3 \times  - 3} }

Multiply the numbers

\sf⟾ \: \purple{6 ^{ - 9} }

To make the power positive, Do the reciprocal of the whole number

\sf⟾ \:  \pink{ \frac{1}{ {6}^{9} } }

<u>Thus</u><u>,</u><u> </u><u>Option</u><u> </u><u>B</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>correct</u><u> </u><u>choice</u><u>!</u><u>!</u><u>~</u>

polet [3.4K]3 years ago
4 0

Answer:

(6^{-2}*6^{5} )^{-3} \\\\(6^{3} )^{-3} \\\\ \frac{1}{(6^{3})^{3}  } \\\\\frac{1}{6^{9} }

Step-by-step explanation:

Option B is correct

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A countries population in 1991 was 231 million in 1999 it was 233
AleksandrR [38]
The answer is:A = 231e^(.0010776*12) = 234 million in 2003 
k=(In(233/231))/(8) 
<span>k=1.00865/8 <===== you used the ratio of 233/321, not the natural log of the ratio. </span>

<span>233/231 = 1.00865 </span>
<span>ln(233/231) = ln(1.00865) = 0.0086207 </span>
<span>k = 0.0086207/8 = 0.0010776 </span>


3 0
4 years ago
A researcher decides to set the significance level to 0.10. If the null hypothesis is true, what is the probability of a Type I
MakcuM [25]

Answer:

the probability of a Type I error is 0.10

Step-by-step explanation:

  Given the data in the question;

significance level ∝ = 0.10

Null H₀ hypothesis is true;

the probability of a Type I error = ?

we know that; a type 1 error is the error of rejecting a Null hypothesis when in reality, it is true. That is false positive.

Hence, our type 1 error will be;

P(rejecting null | null true ) = significance level ∝ = 0.10

Therefore, the probability of a Type I error is 0.10

3 0
3 years ago
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6 0
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NARA [144]
4m+2 (m-5)=26
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Please mark as brainliest if i was the most helpful!
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