Answer:
broad sense heritability = 0.75
Step-by-step explanation:
Step 1: Variables
phenotypic variation (Vp)
genotype variation (Vg)
environment variation (Ve)
broad sense heritability (H)
Step 2: Formulas:
H = Vg / Vp
Vp = Vg + Ve
Vg = Vp - Ve
Step 3: Given data
Vp = 20
Ve = 5
Step 4: Computation
Vg = 20 - 5 = 15
H = 15 / 20
H = 0.75
Hope this helps!
Answer:
400. just use simple devision and it'll tell you.
Answer:
they give us a sense of where a score falls in relation to the mean of its population (in terms of standard deviation of its population), 2) they allow us to compare scores from different distributions, and 3) they can be transformed into percentiles.
Step-by-step explanation: