Question

Identify the factors of 4x2 + 20x + 25.

Answer 1

The answer is C. (2x+5)(2x+5)

Answer 2

Answer:

Option (c) is correct

The factors of  the given equation  $4x^2+20x+25$ are $=\left(2x+5\right)(2x+5)$

Step-by-step explanation:

 Given equation $4x^2+20x+25$

We have to find the factors of given equation and chosoe the correct option.

Consider the given equation  $4x^2+20x+25$

Rewrite 4 as 2²

and 25 as 5²

We have,

$=2^2x^2+20x+5^2$

Apply exponent rule, $a^mb^m=\left(ab\right)^m$

we have,

$=\left(2x\right)^2+20x+5^2$

rewrite 20 x as $\mathrm{\:as\:}2\cdot \:2x\cdot \:5$

we have,

$=\left(2x\right)^2+2\cdot \:2x\cdot \:5+5^2$

Apply algebraic identity $\left(a+b\right)^2=a^2+2ab+b^2$

We have,

$=\left(2x+5\right)^2$

Thus, The factors of  the given equation  $4x^2+20x+25$ are $=\left(2x+5\right)(2x+5)$