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serious [3.7K]
3 years ago
7

Identify the factors of 4x2 + 20x + 25.

Mathematics
2 answers:
creativ13 [48]3 years ago
7 0
The answer is C. (2x+5)(2x+5)
son4ous [18]3 years ago
6 0

Answer:

Option (c) is correct

The factors of  the given equation  4x^2+20x+25 are =\left(2x+5\right)(2x+5)

Step-by-step explanation:

 Given equation 4x^2+20x+25

We have to find the factors of given equation and chosoe the correct option.

Consider the given equation  4x^2+20x+25

Rewrite 4 as 2²

and 25 as 5²

We have,

=2^2x^2+20x+5^2

Apply exponent rule, a^mb^m=\left(ab\right)^m

we have,

=\left(2x\right)^2+20x+5^2

rewrite 20 x as \mathrm{\:as\:}2\cdot \:2x\cdot \:5

we have,

=\left(2x\right)^2+2\cdot \:2x\cdot \:5+5^2

Apply algebraic identity \left(a+b\right)^2=a^2+2ab+b^2

We have,

=\left(2x+5\right)^2

Thus, The factors of  the given equation  4x^2+20x+25 are =\left(2x+5\right)(2x+5)

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