Ask question

Ask question

All categories

2 years ago

7

Jared and Casey splurged on a special dinner for their anniversary. Their dinner cost $262.57, and the local sales tax is 4%. If

they left a 20% tip on the $262.57, how much in total did they pay?

1 answer:

torisob [31]2 years ago

5 0

Hope this helps and that you can see screenshot!

You might be interested in

Consider the trinomial x^2+10x+24

tino4ka555 [31]

Answer:

see explanation

Step-by-step explanation:

(a)

(x + 2)(x + 12) ← expand using FOIL gives

x² + 14x + 24 ≠ x² + 10x + 24

(b)

consider the factors of the constant term (+ 24) which sum to give the coefficient of the x- term (+ 10)

the factors are + 6 and + 4 , since

6 × 4 = 24 and 6 + 4 = 10 , then

x² + 10x + 24 = (x + 6)(x + 4)

8 0

2 years ago

Question 7 (3 points) This scatter plot shows the number of trees planted and the amount of time that has passed (in hours). Bas

Alexandra [31]

Answer:

According to the scatter plot given, and studying that, we get that the most likely number of trees planted in 12 hours will be 13 trees.

Hope my answer helps :)

7 0

3 years ago

Please help me ----------------

Brut [27]

Answer:

C = 43.98 in

Step-by-step explanation:

Radius = 7

C / d = pi

C = pi * d

C = pi * 14

7 0

3 years ago

Maggie graphed the image of a 90 counterclockwise rotation about vertex A of . Coordinates B and C of are (2, 6) and (4, 3) and

Lemur [1.5K]

Answer:

A(2,2)

Step-by-step explanation:

Let the vertex A has coordinates $(x_A,y_A)$

Vectors AB and AB' are perpendicular, then

$\overrightarrow {AB}=(2-x_A,6-y_A)\\ \\\overrightarrow {AB'}=(-2-x_A,2-y_A)\\ \\\overrightarrow {AB}\perp\overrightarrow {AB'}\Rightarrow \overrightarrow {AB}\cdot \overrightarrow {AB'}=0\Rightarrow (2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0$

Vectors AC and AC' are perpendicular, then

$\overrightarrow {AC}=(4-x_A,3-y_A)\\ \\\overrightarrow {AC'}=(1-x_A,4-y_A)\\ \\\overrightarrow {AC}\perp\overrightarrow {AC'}\Rightarrow \overrightarrow {AC}\cdot \overrightarrow {AC'}=0\Rightarrow (4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0$

Now, solve the system of two equations:

$\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.$

Subtract these two equations:

$5x_A-y_A-8=0\Rightarrow y_A=5x_A-8$

Substitute it into the first equation:

$x_A^2+(5x_A-8)^2-8(5x_A-8)+8=0\\ \\x_A^2+25x_A^2-80x_A+64-40x_A+64+8=0\\ \\26x_A^2-120x_A+136=0\\ \\13x_A^2-60x_A+68=0\\ \\D=(-60)^2-4\cdot 13\cdot 68=3600-3536=64\\ \\x_{A_{1,2}}=\dfrac{60\pm8}{2\cdot 13}=\dfrac{34}{13},2$

Then

$y_{A_{1,2}}=5\cdot \dfrac{34}{13}-8 \text{ or } 5\cdot 2-8\\ \\=\dfrac{66}{13}\text{ or } 2$

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)

8 0

3 years ago

Can someone help

iVinArrow [24]

3 is multiplying by itself 7 times. The answer is 3 superscript 7.

7 0

3 years ago

Read 2 more answers