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olganol [36]
2 years ago
14

Combine these radicals. 3/2-5/2

Mathematics
2 answers:
Naddika [18.5K]2 years ago
8 0

Answer:

-1

Step-by-step explanation:

Ivenika [448]2 years ago
6 0

Answer:-2

Step-by-step explanation:

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Determine the best method to solve the system of equations. Then solve the system.
maxonik [38]

Answer:

x=1  y = -1/2

(1,-1/2)

Step-by-step explanation:

7x-2y=8  

5x+2y=4

I would use elimination since we have 2y in one equation and -2y in the other

7x-2y=8  

5x+2y=4

--------------------

12x = 12

Divide each side by 12

12x/12 = 12/12

x =1

The substitute back into equation 2

5(1) +2y = 4

5 +2y = 4

Subtract 5

5-5+2y = 4-5

2y = -1

Divide by 2

2y/2 = -1/2

y = -1/2

8 0
3 years ago
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Mrs. Giuntini’s lawn is triangle shaped with a base of 25 feet and a height of 10 feet. What is the area of Mrs. Giuntini’s lawn
Vedmedyk [2.9K]

area \:  =  \frac{1}{2} bh \\ area \:  =  \frac{1}{2} (25)(10) \\ area =  \frac{1}{2} 250 \\ area = 125 \: feet ^{2}

4 0
3 years ago
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WHAT ORDER DO THESE GO IN HELPPPPPP AII!?
ra1l [238]

Answer:

They are correct. :)

Step-by-step explanation:

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What are the zeros of the function f(x)=x2+12x+38
Artemon [7]

Answer:

The zero would be -2.714 (x-intercept)

6 0
3 years ago
you measure the period of a mass oscillating on a vertical spring ten times as follows: period (s): 1.06, 1.31, 1.28, 0.99, 1.48
lidiya [134]

The mean and (sample) standard deviation σ = 0.2098.

<h3>What exactly would the standard deviation indicate?</h3>

The term "standard deviation" (or "") refers to the degree of dispersion of the data from the mean. Data are grouped around the mean when the standard deviation is low, and are more dispersed when the standard deviation is high.

<h3>According to given information:</h3>

The mean is the product of the dataset's total and the sample size. Mathematically.

\bar{x}=\frac{\sum X_i}{N}

The individual periods are Xi.

The sample size is N.

\sum X i = 1.06 + 1.31 + 1.28 + 0.99,+  1.48 + 1.37+  0.98 + 1.31 + 1.59 + 1.55

\sum X i = 12.92

N = 10

While substituting the value we get:

x = 12.96/10

x = 1.292

The samples' average is 1.292.

The standard deviation:

\sigma=\sqrt{\frac{\sum(x-\bar{x})^2}{N}}

\sum(x-\bar{x})^2 = (1.48-1.292)^2+(1.37-1.292)^2+(0.98-1.292)^2+(1.31-1.292)^2+(1.59-1.292)^2+(1.55-1.292)^2.

\sum(x-\bar{x})^2 = 0.43996

Putting into the formula we get:

\sigma=\sqrt{\frac{0.43996}{10}}

σ = √(0.043996)

σ = 0.2098

The mean and (sample) standard deviation σ = 0.2098.

To know more about standard deviation visit:

brainly.com/question/18521100

#SPJ4

I understand that the question you are looking for is:

You measure the period of a mass oscillating on a vertical spring ten times as follows:

Period (s): 1.06, 1.31, 1.28, 0.99, 1.48, 1.37, 0.98, 1.31, 1.59, 1.55

Required:

What are the mean and (sample) standard deviation?

a. Mean: 1.228, Standard Deviation: 0.2135

b. Mean: 1.325, Standard Deviation: 0.1674

c. Mean: 1.292. Standard Deviation: 0.2211

d. Mean: 1.228, Standard Deviation: 0.2098

e. Mean: 1.292, Standard Deviation: 0.2135

7 0
1 year ago
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