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2 years ago

8

Logan is going to use a computer at an internet cafe. The cafe charges an initial fee to use the computer and then an additional

price per minute of usage. Let C represent the total cost of using a computer for t minutes at the internet cafe. The table below has select values showing the linear relationship between t and C. Determine the initial charge to use a computer.

1 answer:

aalyn [17]2 years ago

6 0

Answer:

$6

Step-by-step explanation:

Hourly rate is $1.5

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PLEASE HELP?! I️ GOT TONS OF HW DUE TOMORROW MORNING! Translate 75% of 266 to an equation, and then solve.

notka56 [123]

75% equals .75
Therefore,
$.75 \times 266$
The awnser equals
$199.5$

4 0

4 years ago

Which point is on the graph of the equation y = 2 x - 5?

Aneli [31]

Answer:

4

Step-by-step explanation:

the correct answer is number 4

if X = 2 ==> 2x -5 = 2(2) -5 = 4 - 5 = -1

4 0

3 years ago

Read 2 more answers

Match the values associated with this data set to their correct descriptions. {6, 47, 49, 15, 43, 41, 7, 36}

Brums [2.3K]

1st quartile: 11

median: 38.50000

3rd quartile: 45

<h3>According to the given information:</h3>

Order these numbers in increasing order: 6, 7, 15, 36, 41, 43, 47, 49
There is a 38.5 median (it is the mean of 36 and 41 - the pair of middle entries).
6,7,15,36, or the left-most half of the data, make up the sample.
The median of the lower half is 11, which is the first quartile (it is the mean of 7 and 15 - the pair of middle entries).
41, 43, 47, and 49, which are the data points in the upper half, are to the right of the median.
The median of the upper half is 45 in the third quartile (it is the mean of 43 and 47 - the pair of middle entries).
The biggest value deviates 10.5 from the median (49-38.5)

Measure descriptive statistics

1st quartile: 11

median: 38.50000

3rd quartile: 45

To know more about quartile visit:

brainly.com/question/8737601

#SPJ4

I understand that the question you are looking for is :

2 Drag the tiles to the boxes to form correct pairs. Match the values associated with this data set to their correct descriptions. {6, 47, 49, 15, 43, 41, 7, 36} first quartile 38.5 median 11 third quartile 10.5 the difference of the largest value and the median 45

7 0

2 years ago

6th grade math please help

Sholpan [36]

Answer: 9x-3x and 5x+x

Step-by-step explanation:

1. Brianna's thinking is incorrect because of course, when x is 0, the expression will equal whatever value isn't an x term. To find equivalent expression, you actually need to find which expressions have the same amount of x terms and the same value.

2. Expressions A and C are equivalent.

3. Expression A can be simplified, as you can do 9x - 3x = 6x, so your final expression would be 6x - 4. Expression C can also be simplified with 5x + x = 6x, which can then also be written as 6x - 4. This means both expressions have the same amount of x terms, and the same value, so they are equivalent.

6 0

3 years ago

Read 2 more answers

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago