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4 years ago

What fraction has a value that’s equal to 7/8?

Mathematics

1 answer:

netineya [11]4 years ago

8 0

Answer:14/16

Step-by-step explanation:

14/16

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3 years ago

Common denominator of 5 6 7

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5, 10, 15, 20, 25, 30, 35, 40, 45, 50, ... 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, ... 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, ...

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3 years ago

PLEASE HELP ASAP

maria [59]

Answer:

First option: $3x^2-5x=-8$

Second option: $2x^2=6x-5$

Fourth option: $-x^2-10x=34$

Step-by-step explanation:

Rewrite each equation in the form $ax^2+bx+c=0$ and then use the Discriminant formula for each equation. This is:

$D=b^2-4ac$

1) For $3x^2-5x=-8$ :

$3x^2-5x+8=0$

Then:

$D=(-5)^2-4(3)(8)=-71$

Since $D$ this equation has no real solutions, but has two complex solutions.

2) For $2x^2=6x-5$ :

$2x^2-6x+5=0$

Then:

$D=(-6)^2-4(2)(5)=-4$

Since $D$ this equation has no real solutions, but has two complex solutions.

3) For $12x=9x^2+4$ :

$9x^2-12x+4=0$

Then:

$D=(-12)^2-4(9)(4)=0$

Since $D=0$ this equation has one real solution.

4) For $-x^2-10x=34$ :

$-x^2-10x-34=0$

Then:

$D=(-10)^2-4(-1)(-34)=-36$

Since $D$ , this equation has no real solutions, but has two complex solutions.

3 0

3 years ago

What is the pattern in the values as the exponents increase?

nirvana33 [79]

Answer:

"Multiply the previous value by 2"

Step-by-step explanation:

Let's check the first 2 terms for all the answer choices.

1. Add $\frac{1}{16}$ to the previous value:

$\frac{1}{32}+\frac{1}{16}=\frac{3}{32}$

Doesn't match.

2. Subtract $\frac{1}{16}$ from the previous value:

$\frac{1}{32}-\frac{1}{16}=-\frac{1}{32}$

Doesn't match.

3. Divide the previous value by 2:

$\frac{\frac{1}{32}}{2}\\=\frac{1}{32}*\frac{1}{2}=\frac{1}{64}$

Doesn't match.

4. Multiply the previous value by 2:

$\frac{1}{32}*2=\frac{2}{32}=\frac{1}{16}$

DOES WORK!

Also, doing the same thing with all the other values would give us matching answer. So this choice is right.

7 0

3 years ago

Read 2 more answers