Question

Write the first five terms of the sequence in which the nth term is a_n=(n+1)!/n+1.

Answer 1

Answer: a) 1,2,6,24,120

Step-by-step explanation:

Answer 2

Answer:a) 1,2,6,24,120

Step-by-step explanation:

The formula for the nth term of the sequence is expressed as

n=(n+1)!/n+1

For the first term, n = 1. Therefore,

(1+1)!/(1+1) = 2!/2 = (2×1)/2 = 1

For the second tern, n = 2. Therefore,

(2+1)!/2+1 = 3! /3 = (3×2×1)/3 = 6/3 = 2

For the third term, n = 3, therefore

(3+1)!/3+1 = 4!/4 =(4×3×2×1)/4 = 6

For the fourth term, n = 4. Therefore

(4+1)!/4+1 = 5!/5 = (5×4×3×2×1)/5 = 24

For the fifth term, n = 5. Therefore

(5+1)!/5+1 = 6!/6 = 6× 5×4×3×2×1)/6 = 120