Answer:
(2 , 30) & (4, 60)
Step-by-step explanation:
y = 15x
When x = 2 , y = 15*2 = 30
When x = 4 ; y = 15 *4 = 60
Step #1 for both: figure out which interval your x-value fits into.
For f(-2), x=-2 and -2 fits with x ≤ -2, the top interval.
For f(3), x=3 and 3 fits into -2 < x ≤ 3, the middle interval.
Step #2 for both, plug in your x-value to the piece of the function that fits with that interval.
For f(-2), we know x≤-2, so we use 2x+8 to evaluate x=-2.
For f(3), we know -2
f(-2) = 2(-2)+8 = -4+8 = 4
f(3) = (3)^2 -3 = 9-3 = 6
It would be 2x/3y assuming that’s meant to say 15y^2
6 because 6X6=36 and a square has all sides equal.
Answer:
These results, 7 and 9, have a product of 63, as stated.
Step-by-step explanation:
Represent the first odd number by x and the first consecutive odd number by x + 2. Then the product of these two numbers is x(x + 2) and it equals 63.
Solve for x. Perform the indicated multiplication, obtaining
x^2 + 2x - 63 = 0
Solve this by factoring: (x + 9)(x - 7) = 0
Then x could be either -9 or +7. If we let x = 7 then the first consecutive odd number is 7 + 2, or 9. These results, 7 and 9, have a product of 63, as stated.
