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yuradex [85]
2 years ago
14

State if the two triangles are similar and the rule that applies.

Mathematics
1 answer:
kobusy [5.1K]2 years ago
3 0

Answer:

The SAS rule states that two triangles are similar if the ratio of their corresponding two sides is equal and also, the angle formed by the two sides is equal. Side-Side-Side (SSS) rule: Two triangles are similar if all the corresponding three sides of the given triangles are in the same proportion.

Step-by-step explanation:

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6 × 3 − (4 × 3) + 16 ÷ 4 = 11
rjkz [21]

Answer:

2

Step-by-step explanation:

6x3 = 18

4x3 = 12

18 - 12 = 6

16 / 4 = 4

6 - 4 = 2

4 0
3 years ago
Answer please i am literally crying because i will get in trouble if i dont do it
alekssr [168]
Convert percentages to units.
100% - 20% = 80% = 0.8
100% - 25% = 75% = 0.75

Then multiply those together:
0.8*0.75=0.6=60%

100% - 60% = 40%. That's the overall price percentage reduction.


P.S. You can convert percentages to units by diving % by 100 for example 100% divided by 100 is equal to 1.
And vice versa aka multiply units by 100 and you get %, for example 0.8 times 100 is 80%



3 0
3 years ago
Read 2 more answers
If f (x)=8-5x, find the value of f(2-k)
Helen [10]

Hello from MrBillDoesMath!

Answer:

f(2-k) = -2 + 5k

Discussion:

If f(x) = 8 - 5x , then

f(2-k) = 8 - 5(2-k) =>

f(2-k) = 8 - 10 + 5k =>

f(2-k) = -2 + 5k

Regards,  

MrB


6 0
3 years ago
Help me please don’t use me for points
Norma-Jean [14]

Answer:

9x+3

Step-by-step explanation:

First join the x terms, and you will find 9x (1x+8x), then join the numbers, and you get 3 (-7+10)

Hope it helps!

5 0
3 years ago
Read 2 more answers
The area of a circular oil slick on the surface of the sea is increasing at a rate of [150m^2/s] how fast is the radius changing
Akimi4 [234]

Answer with Step-by-step explanation:

We are given that

\frac{dA}{dt}=150m^2/s

a.Radius =25 m

We have to find rate of change of radius.

We know that

Area of circle,A=\pi r^2

Differentiate w.r.t time

\frac{dA}{dt}=2\pi r\frac{dr}{dt}

Substitute the values then we get

150=2\pi (25)\frac{dr}{dt}

\frac{dr}{dt}=\frac{150}{50\pi}=\frac{3}{\pi} m/s

\frac{dr}{dt}=\frac{3}{\pi} m/s

b.A=1000m^2

Substitute the values then we get

1000=\pi r^2

\pi=3.14

r^2=\frac{1000}{3.14}

r=\sqrt{\frac{1000}{3.14}}=17.8m

\frac{dA}{dr}=2\pi r\frac{dr}{dt}

Substitute the values then we get

150=2\pi(17.8)\frac{dr}{dt}

\frac{dr}{dt}=\frac{150}{2\pi(17.8)}=\frac{150}{35.6\pi}m/s

\frac{dr}{dt}=\frac{75}{17.8\pi}m/s

4 0
2 years ago
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