-8c^3/d^6 is equivalent to the expression
Answer:
Step-by-step explanation:
Evaluate g(- 4) and f(- 4) by substituting x = - 4 into g(x) and f(x), that is
f(- 4) = - 10(- 4) + 9 = 40 + 9 = 49
g(- 4) = (- 4)² + 12 = 16 + 12 = 28
Then
= = 
Start with 180.
<span>Is 180 divisible by 2? Yes, so write "2" as one of the prime factors, and then work with the quotient, 90. </span>
<span>Is 90 divisible by 2? Yes, so write "2" (again) as another prime factor, then work with the quotient, 45. </span>
<span>Is 45 divisible by 2? No, so try a bigger divisor. </span>
<span>Is 45 divisible by 3? Yes, so write "3" as a prime factor, then work with the quotient, 15 </span>
<span>Is 15 divisible by 3? [Note: no need to revert to "2", because we've already divided out all the 2's] Yes, so write "3" (again) as a prime factor, then work with the quotient, 5. </span>
<span>Is 5 divisible by 3? No, so try a bigger divisor. </span>
Is 5 divisible by 4? No, so try a bigger divisor (actually, we know it can't be divisible by 4 becase it's not divisible by 2)
<span>Is 5 divisible by 5? Yes, so write "5" as a prime factor, then work with the quotient, 1 </span>
<span>Once you end up with a quotient of "1" you're done. </span>
<span>In this case, you should have written down, "2 * 2 * 3 * 3 * 5"</span>
Answer:
- <em><u>5.6875 in</u></em>
Explanation:
At the point of tangency, the <em>tangent </em>to a circle and the <em>radius</em> form a right triangle (the radius is perpendicular to the tangent).
Here you are given the length of the tangent (6in), and the distance from the bisected vertex to the circle (2.75 in)
I tried to upload the drawing but the tool is not allowing it now.
In the figure:
- The length of the tangent (6 in) is one leg of the triangle
- The distance from vertex and the circle (2.75in) along with the radius forms the hypotenuse of the right triangle: 2.75 + r.
- The other leg is the radius, r.
Then, you can use Pythagorean theorem:
Solve:
- r² + 36 = r² + 5.5r + 7.5625
The solution is in inches: r = 5.6875 inches ← answer
