<span><span>square root of 512k^2
</span></span><span>Problem:</span><span>Simplify
<span> <span><span>512<span>k2</span> </span><span>−−−−−</span>√</span> </span>Step-By-Step Solution:Rewrite <span>512<span>k2</span></span> as <span><span><span>(<span>16k</span>)</span>2</span>⋅2</span>.More Steps<span><span><span><span>(<span>16k</span>)</span>2</span>⋅2</span><span>−−−−−−−−</span>√</span>Pull terms out from under the radical.<span><span><span>16k</span><span>2√</span></span></span></span>
Answer: a) 2:1. b) 3. c) Perimeter of ΔEFG=36 Perimeter of ΔHIJ=18. d) 2:1
Step-by-step explanation:
a) Find the ratio of GF and JI. 16:8. Simplify by dividing both by 8 to get 2:1.
b) Set up this equation: 6/16=x/8. Cross-multiply. 6*8=48. Divide by 16. 48/16=3.
c) First find the length of one half of GF by dividing 16 by 2. 16/2=8. Set up the Pythagorean theorem. 8^2+6^2=c^2. Square 8 and 6. 64+36=c^2. Add 64 and 36. 100=c^2. Find the square root of 100. c=10.
EF and EG both measure 10 since they are shown to be congruent. 10+10+16=36.
Next find the length of one half of JI by dividing 8 by 2. 8/2=4. Set up the Pythagorean theorem. Since we know x=3, it will be 4^2+3^2=c^2. Square both 4 and 3. 16+9=c^2. Add 16 and 9. 25=c^2. Find the square root of 25. c=5.
HJ and HI both measure 5 since they are congruent. 5+5+8=18.
d) Find the ratio of the perimeters of ΔEFG and ΔHIJ. 36:18. Simplify by dividing both by 6 to get 6:3. Simplify further by dividing both by 3 to get 2:1.
We have the following table:
545-534.2 = 10.8
545-556.4 = -11.4
545-554.0 = -9
545-535.3 = 9.7
write them as a positive and negative rational numbers
positive:
9.7 = 9 7/10
10.8 = 10 4/5
negative:
-11.4 = -11 2/5
-9 = -9
the differences from least to greatest
-11 2/5
-9
9 7/10
10 4/5
Answer:
Y=3/2x - 3/2
Step-by-step explanation:
To find the inverse, switch the x and y in the equation. Then solve for y.
Y=2/3x+1
X=2/3y+1
X-1=2/3y
3/2(x-1)=y
3/2x-3/2=y
