Answer:
The equation would be y = -1/3x + 4
Step-by-step explanation:
The first step to finding this equation needs to be solving the first equation for y so that we can find the slope.
-3x + y = 1
y = 3x + 1
Now that we have the slope of 3, we know the slope of a perpendicular line would be -1/3. This is because perpendicular lines have opposite and reciprocal slopes. We can then use this and the point to solve in point-slope form.
y - y1 = m(x - x1)
y - 2 = -1/3(x - 6)
y - 2 = -1/3x + 2
y = -1/3x + 4
The graph is **increasing on the interval (-2, 1)**because the graph has a positive slope from x=-2 to x=1. It’s **decreasing at the intervals (-infinity, -2) and (1, infinity)**because the graph has a negative slope between the x values -infinity to -2 and is also decreasing between the x values of 1 and infinity.
Answer:
![\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D)
Step-by-step explanation:
We are required to simplify the quotient: ![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D)
Since the <u>numerator and denominator both have the same root index</u>, we can therefore say:
![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}} =\sqrt[3]{\dfrac{60} {20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D%20%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B60%7D%20%7B20%7D%7D)
![=\sqrt[3]{3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%7D)
The simplified form of the given quotient is .
10² - 2 (8) + 11 . Use PEMDAS, which is the order of operation to follow:
P = parenthesis → 10² - 2x8 +11
E = exponent → 100 - 2x8 +11
M = Multiplication → 100 -16 +11
D = Division → NO DIVISION
A = Addition → 111 -16
S = Subtraction → 95 (answer 3)
Apply the same logic for the 2nd exercice and you will find 26 (I don't see the 26 in your answer but I am sure it's 26)
The answer C make more sense.
