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2 years ago

Pls help, photo below. will give brainliest

Mathematics

1 answer:

denis-greek [22]2 years ago

7 0

Your bottoms row is
5 22 34 68 ur band

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PLESE HELP GEOMETERY

nalin [4]

In this problem, you must use SohCahToa which basically means:

Sin - opposite over hypotenuse

Cosine - adjacent over hypotenuse

Tangent - Opposite over hypotenuse

So in this picture we have 4 -which is on the opposite side of x - and a 5 -which is the hypotenuse of the triangle. This means we must use sin.

Using a calculator you put in:

$sin^{-1} (\frac{4}{5} )$

Your answer is 53.13 degrees

4 0

3 years ago

3x+5y=12 solve for x

Ivenika [448]

Answer:

x=4-5/3y

Step-by-step explanation:

3x+5y=12 make x on one side

3x=12-5y divide everything by 3

x=4-5/3y

7 0

4 years ago

A workbook contains 1,213 problems. If 837 of the problems have been solved, how many unsolved problems are left in the workbook

11Alexandr11 [23.1K]

Answer:

376

Step-by-step explanation:

This is a subtraction problem.

1,213 - 837 =

1,213

- 837

-----------

376

Answer: 376

3 0

3 years ago

Read 2 more answers

A tank contains 200 liters of fluid in which 50 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu

mel-nik [20]

At the start, the tank contains A(0) = 50 g of salt.

Salt flows in at a rate of

(1 g/L) * (5 L/min) = 5 g/min

and flows out at a rate of

(A(t)/200 g/L) * (5 L/min) = A(t)/40 g/min

so that the amount of salt in the tank at time t changes according to

A'(t) = 5 - A(t)/40

Solve the ODE for A(t):

A'(t) + A(t)/40 = 5

e^(t/40) A'(t) + e^(t/40)/40 A(t) = 5e^(t/40)

(e^(t/40) A(t))' = 5e^(t/40)

e^(t/40) A(t) = 200e^(t/40) + C

A(t) = 200 + Ce^(-t/40)

Given that A(0) = 50, we find

50 = 200 + C ==> C = -150

so that the amount of salt in the tank at time t is

A(t) = 200 - 150 e^(-t/40)

7 0

4 years ago

Jazmin is completing an art project. She has two pieces of construction paper. The first piece is 4 4 4444 inches wide and the s

poizon [28]

Answer:

Each strip should 11 inches wide.

Step-by-step explanation:

We are told that Jazmin has two pieces of construction paper. The first piece is 44 inches wide and the second piece is 33 inches wide. Jazmin wants to cut the paper into strips that are equal in width and are as wide as possible.

To find the greatest possible width of each strip we will find GCF of 44 and 33.

Factors of 44 are: 1, 2, 4, 11, 22, 44.

Factors of 33 are: 1, 3,11, 33.

We can see that 11 is the greatest common factor of 44 and 33 as 11*4=44 and 11*3=33, therefore, Jasmine should cut each strip 11 inches wide.

5 0

4 years ago

Read 2 more answers