Find the qoutient 1 1/6 / 1/12

Mathematics

1 answer:

anygoal [31]2 years ago

8 0

Answer:

Step-by-step explanation:

$1\frac{1}{6}\div\frac{1}{12}\\ \\ \frac{7}{6}\div\frac{1}{12}\\ \\\frac{7}{6}*\frac{12}{1}\\ \\\frac{84}{6}\\ \\14$

You might be interested in

Part A: Find a rational number that is between 5.2 and 5.5. Explain why it is rational. (2 points) Part B: Find an irrational nu

Ulleksa [173]

The answer
a rational number that is between 5.2 and 5.5
first, a rational number is a decimal number that the number after the dot can be ended. for example
1/2 = 0.5 is rational, 2 is rational because 2 = 2. 0,

so a rational number between 5.2 and 5.5 can be 525 /100
because this rational number can be written as 525 /100 = 5.25
and 5.2 less than 5.25 less than 5.5

an irrational number is a decimal number that the number after the dot cannot be ended. for example 1/3 = 0.3333333333......

so so an irrational number between 5.2 and 5.5 can be √30
because √30 can be written as √30 = 5,477225575051661134569........

and 5.2 less than 5.47 less than 5.5

5 0

3 years ago

Please help, will mark branliest and 33 points!

LuckyWell [14K]

Answer:

Area = 45 sq ft

Step-by-step explanation:

Scale conversion:

2 inches = 6 feet

5 inches = 15 feet

Area = 1/2 base times height

Area - 1/2 x 6 x 15

Area = 45 ft squared

4 0

2 years ago

68 - 4 × (6 - 4)4 pls help o-o

Alika [10]

Answer:

Here you go!, hope it helped. 68-32x

7 0

2 years ago

Read 2 more answers

5-5|5x+3|=-10 solve

AleksAgata [21]

Exact Form:

x = 0 , −6/5

Decimal Form:

x = 0 , − 1.2

Mixed Number Form:

x = 0 , − 1 1/5

6 0

2 years ago

Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive

VikaD [51]

Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

$\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}$

recall that

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}$

therefore, let's just plug that on the remaining ones,

$\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}$

now, let's rationalize the denominator on tangent and secant,

$\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}$

3 0

3 years ago