3 years ago

Solve the systems of equation by substitution method.2x+y=13x-y=4

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

5 0

Answer:

x=1, y=-1. (1, -1).

Step-by-step explanation:

2x+y=1

3x-y=4

-------------

y=3x-4

2x+3x-4=1

5x-4=1

5x=1+4

5x=5

x=5/5

x=1

y=3(1)-4=3-4=-1

You might be interested in

8ftx4ftx5ft what is the diameter

Serggg [28]

Answer:

nothing

Step-by-step explanation:

6 0

2 years ago

Combine the like to simplify the expression: -5y + 12 + 8y − 6 − 2 =

ANTONII [103]

First, let's move combine like terms:

-5y + 8y = 6 + 2 -12.

3y = -4.

y = -4/3

8 0

3 years ago

Read 2 more answers

Find the distance between the two points.

Ksenya-84 [330]

Hey there!

Distance formula:

d = $\sqrt{(x_{2}-x_{1})+(y_{2}-y_{1}) }$

Plug in variables:

d = $\sqrt{(0-(-6))+(0-(-7))}$

Simplify.

d = $\sqrt{6+7}$

d = $\sqrt{13}$

The distance between the two points is $\sqrt{13}$ units.

Hope this helps!

4 0

3 years ago

Write the equation of the line that passes through the points (-6,-1) and (-4,2). Put your answer in fully simplified point-slop

Archy [21]

$(\stackrel{x_1}{-6}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{-4}-\underset{x_1}{(-6)}}} \implies \cfrac{2 +1}{-4 +6} \implies \cfrac{ 3 }{ 2 }$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{(-6)}) \implies {\large \begin{array}{llll} y +1= \cfrac{3}{2} (x +6) \end{array}}$

4 0

1 year ago

Please help! This is timed

gulaghasi [49]

I think the answer is C 1 2/3

4 0

3 years ago

Read 2 more answers

Solve the systems of equation by substitution method.2x+y=13x-y=4​

Solve the systems of equation by substitution method.2x+y=13x-y=4