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Umnica [9.8K]
2 years ago
10

Amplifica fractia 2 supra 5 pana cand numitorul o sa fie 100

Mathematics
1 answer:
Savatey [412]2 years ago
7 0

Answer:

Step-by-step explanation:

Fractia 2 supra 5 trebuie sa fie egala cu fractia care are numitorul 100

2/5 =  x /100

Cu cat e 100 mai mare decat 5 ?

5 ·? = 100

    ? = 100/5 = 20

Amplifica fractia care ti s-a dat 2/5 cu 20  

2·20 /5·20 = 40 /100

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Step-by-step explanation:

B and C

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Cant figure it out. Help please
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area = 160 cm²

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-6/13 - (-7/15)<br> pls solve it for me !!! :)
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Answer:

First, make the double negative a positive.

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Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the othe
8090 [49]

Answer:

The faster bus moves at 83mi/h and the slower one moves at 69mi/h.

Step-by-step explanation:

Let's define:

R₁ = rate of bus 1, this is the faster one.

R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

Distance = Speed*Time.

If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

R₁*2h + R₂*2h = 304 mi

Then we have the two equations:

R₂ = R₁ - 14mi/h

R₁*2h + R₂*2h = 304 mi

The first step is to replace the first equation in the second one, to get:

R₁*2h + (R₁ - 14mi/h)*2h = 304 mi

And now we can solve this for R₁.

R₁*2h + R₁*2h - 14mi/h*2h = 304 mi

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R₁*4h = 304mi + 28mi = 332mi

R₁ = 332mi/4h = 83mi/h

The faster bus moves at 83mi/h

And we know that the slower one moves at 14mi/h slower than this, then:

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2 years ago
Math question help me
JulsSmile [24]

Answer:

3 grams

Step-by-step explanation:

on the left side there is 3 circles and every circle is 3 grams, so there is 9 grams plus 6 squares for 2 grams its 12 . 9+12 =21 and two triangles with x mass

on the right side there is 2 circles , 2×3 = 6, and 3 squares, 3×2 = 6. 6+6=12 +5x

both sides are equal so we have

21+2x=12+5x

21-12=5x-2x

9=3x

x=3

6 0
2 years ago
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