2 years ago

Write a verbal phrase for each of the following algebraic expressions.

Mathematics

1 answer:

Scrat [10]2 years ago

3 0

Answer:

a. the product of 11 and x

b. 9 greater than x

c. x less than 18

d. the product of 4 and the difference of x and 3

Step-by-step explanation:

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('h(I) = -35<br>(h(n) = h(n - 1)×2<br>h(3) =

qwelly [4]

Answer:

h(3)=n(h_3)×3that is the answer

3 0

3 years ago

Find the measure of

adell [148]

I don’t know what the options are but I think it is 95 because 120-25 = 95

5 0

2 years ago

Which of the following equations are equivalent to -2m - 5m - 8 = 3 + (-7) + m?

grandymaker [24]

-2m - 5m = -7m
-7m - 8 = 3 -7 + m
3 - 7 = -4
-7m - 8 = m - 4
-7m - 8 + 8 = m - 4 + 8
-7m = m + 4
-7m - m = m + 4 - m
-8m = 4
-8m/-8 = 4/ -8
FINAL = m= -1/2 = -0.5

4 0

3 years ago

) Using the chart, approximate the limit of the function f(x) = sin x/ x as x approaches zero. Note the numbers are in radians:

Rashid [163]

Answer:

Step-by-step explanation:

We are given that

$f(x)=\frac{sinx}{x}$

Numbers are in radians

Substitute x=-1

$f(-1)=\frac{sin(-1)}{-1}=0.84$

Substitute x=-0.25

$f(-0.25)=\frac{Sin(-0.25)}{-0.25}=0.989$

Substitute x=-0.01

$f(-0.01)=\frac{sin(-0.01)}{-0.01}=0.999$

Substitute x=-0.005

$f(-0.005)=\frac{sin(-0.005)}{-0.005}=0.999$

Substitute x=0.005

$f(0.005)=\frac{sin(0.005)}{0.005}=0.999$

Substitute x=0.01

$f(0.01)=\frac{sin(0.01)}{0.01}=0.999$

Substitute x=0.25

$f(0.25)=\frac{sin(0.25)}{0.25}=0.989$

Substitute x=1

$f(1)=\frac{sin(1)}{1}=0.84$

Therefore, $\lim_{x\rightarrow 0}\frac{sinx}{x}=1$

8 0

3 years ago

Will give 15 pts if you answer this question

Zigmanuir [339]

Your answer is 1,027 :))))))

4 0

3 years ago

Read 2 more answers