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alexira [117]
2 years ago
10

Need help please with this puzzle

Mathematics
1 answer:
Mrrafil [7]2 years ago
7 0

Answer:

5th one is the correct ans

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A briefcase has a three- digit lock code that doesn't include zero as a digit. What is the probability that the lock code consis
storchak [24]

Answer:

1/21.

Step-by-step explanation:

There are 9 digits and the total number of permutations of 3 from 9 is 9P3

= 9!/6!  = 504.

There are 4 even digits so the number of permutations of 3 from these 4 is 4!  (4-3)!  = 4*3*2 = 24.

So the required probability =  24/504

= 1/21.

5 0
3 years ago
Please help me solve this problem
Maksim231197 [3]

Answer:

i think the answer is 58

but i'm not sure....

check it again with someone else ...

Step-by-step explanation:

90+32=122

180-122=58

4 0
3 years ago
Which functions have a horizontal asymptote? Check all that apply.
Anarel [89]
If I could see the photo I could help you answer the question
6 0
3 years ago
Read 2 more answers
Thomas buys 6 souvenirs for his friends and family. Each gift takes up 1/15 of his suitcase. If he has two suitcases, how much r
Gala2k [10]

Answer:

<u>Thomas still has 1 3/5 suitcases available for his own belongings.</u>

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Number of souvenirs bought by Thomas = 6

Space that each souvenir takes of Thomas suitcase = 1/15

Number of Thomas suitcases = 2

2.  How much room is left for his own belongings in his suitcases?

Let's find out how much space the souvenirs take:

Number of souvenirs * Space that each souvenir takes

6 * 1/15 = 6/15 = 2/5 (Dividing by 3 the numerator and the denominator)

The souvenirs take 2/5 of one suitcase.

Now, we can calculate the room that is left for Thomas' belongings.

2 Suitcases - 2/5 for the souvenirs

2 - 2/5 = 10/5 - 2/5 = 8/5 = 1 3/5

<u>Thomas still has 1 3/5 suitcases available for his own belongings.</u>

6 0
3 years ago
Find the perimeter ​
Inga [223]

Answer:

56

Step-by-step explanation:

Perimeter= 4S

Perimeter= 4(5)

Perimeter= 20

Perimeter 2= 2(L+W)

Perimeter 2= 2(11+7)

Perimeter 2= 22+14

Perimeter 2= 36

Total Perimeter= P1+P2

Total Perimeter= 20+36

Total Perimeter= 56

6 0
3 years ago
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