A keyboard would be considered what 2 things

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

2 years ago

Describe the tools that are required to accomplish each step in the data management process.

RideAnS [48]

Answer: The tools which are required to accomplish each step in the data management process are:

1. Cloud Data Management tools.

2. Master Data Management (MDM) tools.

3. Reference Data Management (RDM) tools.

4. ETL tools.

5. Data visualization and analytics tools

Explanation:

Cloud Data Management tools with the help of various API's are able to connect multiples system with their data to the cloud. examples are amazon cloud, google API cloud.

MDM tools are used for creation and maintenance of reference data. example are Profisee

RDM tools is used with the MDM tools and are use to define the businesss processes over the reference data. Examples are Collibra.

ETL tools helps to load data of an organisation to data warehouses after transformation and testing the data pipeline constituting the data from different databases.

Data visualization analytics tools helps to extract and generate report from the big sets of data which can help an organisation to take business decisions.

6 0

3 years ago

Read 2 more answers

In terms of resource utilization, a /an application may require higher local

aksik [14]

Answer: A) Installed

Explanation: Installed application work on the system on which they are installed .They are supposed to persist the required speed of processing to execute the task ,enough memory and other resources as well to fulfill the need of the application functioning.

Other option is incorrect because cloud based application run with help of internet service via web browser so they resources in this applications based on the internet connectivity and browser's speed .Thus, the correct option is option(A).

3 0

3 years ago

Which statement is accurate to describe a spreadsheet versus an Excel workbook?

Tomtit [17]

C is the correct answer

5 0

2 years ago

A group of computers that are interconnected in order to share information or documents is called a _____.

xxMikexx [17]

Computer Network, surely!

"Network" implies combination of all these computers!

7 0

2 years ago