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Angelina_Jolie [31]
2 years ago
5

you have a shop in Salem, Illinois, that sells specialty chocolates. Some customers from France have started placing orders. Whi

ch data regulation must you adhere to for your sales to France?

Computers and Technology
1 answer:
Vladimir79 [104]2 years ago
4 0

The data regulation which you must adhere to for your sales to France is known as: D. the General Data Protection Regulation.

<h3>What is GDPR?</h3>

GDPR is an acronym for General Data Protection Regulation and it can be defined as a legal framework that was enforced on the 25th of May 2018, so as to sets guidelines for business firms during the collection, processing and use of personal information from individuals that are residing in the European Union (EU) and the European Economic Area such as:

  • Germany
  • France
  • England
  • Spain

This ultimately implies that, the General Data Protection Regulation is a data regulation which you must adhere to for your sales to France.

Read more on GDPR here: brainly.com/question/27416494

#SPJ1

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Answer:

See explaination

Explanation:

#method to print menu & handle user choice

def print_menu(input_str):

#printing menu

print('MENU')

print('c - Number of non-whitespace characters')

print('w - Number of words')

print('f - Fix capitalization')

print('r - Replace punctuation')

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#identifying choice

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#displaying number of words in input_str

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elif choice=='f':

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#displaying results

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#replacing punctuation, displaying updated text

input_str=replace_punctuation(input_str)

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#returning choice and input_str

return choice,input_str

#returns the number of non white space chars in input_str

def get_num_of_non_WS_characters(input_str):

count=0

#looping through each character in input_str

for i in input_str:

if not i.isspace():

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count+=1

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#returns the number of words in input_str

def get_num_of_words(input_str):

#splitting words into list of tokens by space

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count=0

#counting all non empty strings in words list

for i in words:

if len(i)>0:

count+=1

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result=''

for i in input_str:

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if i.islower():

#converting i to upper case, incrementing count

i=i.upper()

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beginning=False

elif i in '?.!':

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beginning=True

result+=i

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#any other character

result+=i

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def replace_punctuation(input_str,exclamationCount =0,semicolonCount=0):

result=''

for i in input_str:

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i='.'

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elif i==';':

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print('semicolonCount:',semicolonCount)

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