Answer: (3x + 11y)^2
Demonstration:
The polynomial is a perfect square trinomial, because:
1) √ [9x^2] = 3x
2) √121y^2] = 11y
3) 66xy = 2 *(3x)(11y)
Then it is factored as a square binomial, being the factored expression:
[ 3x + 11y]^2
Now you can verify working backwar, i.e expanding the parenthesis.
Remember that the expansion of a square binomial is:
- square of the first term => (3x)^2 = 9x^2
- double product of first term times second term =>2 (3x)(11y) = 66xy
- square of the second term => (11y)^2 = 121y^2
=> [3x + 11y]^2 = 9x^2 + 66xy + 121y^2, which is the original polynomial.
24
x
^2
+
54
x
+
21,
if you would like me to explain how to do it, I can in the comments.
Answer:
P(a junior or a senior)=1
Step-by-step explanation:
The formula of the probability is given by:
Where P(A) is the probability of occurring an event A, n(A) is the number of favorable outcomes and N is the total number of outcomes.
In this case, N is the total number of the students of statistics class.
N=18+10=28
The probability of the union of two mutually exclusive events is given by:
Therefore:
P(a junior or a senior) =P(a junior)+P(a senior)
Because a student is a junior or a senior, not both.
n(a junior)=18
n(a senior)=10
P(a junior)=18/28
P(a senior) = 10/28
P(a junior or a senior) = 18/28 + 10/28
Solving the sum of the fractions:
P(a junior or a senior) = 28/28 = 1
The quotient refers to an answer that has been divided.
27658/6 = a quotient of 4 with a remainder of (2/3) (two-thirds)
Answer:
17 years
Step-by-step explanation:
The compound interest formula is ...
A = P(1 +r/n)^(nt)
where P is the principal invested at annual rate r, compounded n times per year for t years.
Filling in the numbers and solving for t, we find ...
16826.03 = 8534(1 +.04/12)^(12t)
16826.03/8534 = 1.0033333...^(12t)
Taking logs, we have ...
log(16826.03/8534) = 12t·log(1.0333333...)
Dividing by the coefficient of t gives ...
log(16826.03/8534)/(12·log(301/300)) = t ≈ 17.000
It will take 17 years for the account balance to reach $16,826.03.
