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Misha Larkins [42]
3 years ago
12

Can someone show me how to get x for both

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
5 0

Answer:

So since the sum of both is 13 because it shows both of the lines connected as a length of lines.

So we add them (14+x)+(x+15) = 13

14+2x+15 = 19+2x = 13

-6=2x

x=

<u>-3</u>

Step-by-step explanation:

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Problem<br> How many numbers between 111 and 100100100 (inclusive) are divisible by 101010 or 777?
olga2289 [7]

I suspect you meant

"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"

• Count the multiples of 10:

⌊100/10⌋ = ⌊10⌋ = 10

• Count the multiples of 7:

⌊100/7⌋ ≈ ⌊14.2857⌋ = 14

• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and

⌊100/70⌋ ≈ ⌊1.42857⌋ = 1

(where ⌊<em>x</em>⌋ denotes the "floor" of <em>x</em>, meaning the largest integer that is smaller than <em>x</em>)

Then using the inclusion/exclusion principle, there are

10 + 14 - 1 = 23

numbers in the range 1-100 that are divisible by 10 or 7. In other words, add up the multiples of both 10 and 7, then subtract the common multiples, which are multiples of the LCM.

6 0
3 years ago
A jar contains two blue and five green marbles. A marble is drawn at random and then replaced. A second marble drawn at random.
DerKrebs [107]

corrected question:A jar contains two blue and five green marbles. A marble is drawn at random and then replaced. A second marble drawn at random. For each of the following, find the probability that: a) both marbles are blue b) both marbles are the same color  c)the marbles are different in color

Answer:

Step-by-step explanation:

<u><em>The probability was done with replacement.</em></u>

Probaility of an event happening=\frac{number of required outcomes}{number of possible outcomes}

number of blue marbles= 2

number of green marbles=5

total number of marbles=7

(a) probability that both marbles are blue = pr(first is blue)*pr(second is blue)

                                  =\frac{2}{7}*\frac{2}{7}

                                   =\frac{4}{49}

(b)probability that both marbles are the same color =pr(first is blue)*pr(second is blue) + Pr(first is green)*Pr(second is green)

   =\frac{4}{49} + \frac{5}{7}*\frac{5}{7}

   =\frac{4}{49} + \frac{25}{49}

 =\frac{29}{49}

(c)Probability that the marbles are different in colors=pr(first is blue)*pr(second is green) + Pr(first is green)*Pr(second is blue)

  =\frac{2}{7}*\frac{5}{7}+ \frac{5}{7}*\frac{2}{7}

           =\frac{10}{49}+\frac{10}{49}

      =\frac{20}{49}

6 0
3 years ago
A tuna can weighs eighty-five grams. What is the weight of eleven tuna cans?
Anika [276]

Answer:

85g*11=935g

Step-by-step explanation:

1 tuna can = 85g

11 tuna cans is= 1*11

so 85g*11

3 0
2 years ago
Read 2 more answers
How much is in a pound?
Sonja [21]
How many ounces in a pound is 16 ounces.
7 0
3 years ago
Read 2 more answers
Soryyyyyyyyyyyyyy this one to
alukav5142 [94]
The answer is B - 43.25


The two congruent sides will have congruent angles. One angle measurement is given. Triangle angles equal 180.

Take 180 and subtract the given angle 93.5. Then divide by 2 to get the measurements x and the other unknown.

180 - 93.5 = 86.5

86.5/2 = 43.25
5 0
2 years ago
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