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3 years ago

If tan 0 = -5, find the cot 0

Mathematics

1 answer:

Irina-Kira [14]3 years ago

4 0

Answer:

Step-by-step explanation:

cot(theta) = 1 / tan(theta)

cot(theta) = 1 / -5

cot(theta) = - 0.2

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The volume of this prism Is ___ cubic inches

hoa [83]

Answer:

The answer is 140 cubic in

Step-by-step explanation:

The formula for the volume of a prism is V=Bh, where B is the base area and h is the height. The base of the prism is a rectangle. The length of the rectangle is 9 cm and the width is 7 cm. The area A of a rectangle with length l and width w is A=lw. Hope this helped! :) (ps. I am sorry if it does not help.)

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2 years ago

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When 31 times a number is increased by 40 the answer is the same as when 200 is decreased by the number

coldgirl [10]

Answer:

Tye answer is 5 becuase 5*31=195 and 200-5=195

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3 years ago

Pls help me solve this

prisoha [69]

B, because it’s saying 119 and over you can play on the junior varsity football team.

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3 years ago

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(7,5), (r,9) m=6 What is r?

Igoryamba

Answer:

The answer is that r = 7/6

Step-by-step explanation:

Given point: (7, 5)

Given slope: m = 6

Use the point slope form of the equation:

y - y1 = m(x - x1)

y - 5 = 6(x - 7)

y - 5 = 6x - 7

y = 6x + 2

Now, find r for the point (r, 9) by substitution:

9 = 6x + 2

6x + 2 = 9

6x = 7

x = 7/6

Proof:

y = 6x + 2

f(x) = 6x + 2

f(7/6) = 6(7/6) + 2

= 42/6 + 2

= 7 + 2 = 9, giving (7/6, 9). r = 7/6

Hope this helps! Have a great day!

4 0

3 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

3 years ago