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Marysya12 [62]
2 years ago
5

Deion drives 7.5 miles in 15 minutes. If he drove one hour in total at the same rate, how far did he go?

Mathematics
1 answer:
PilotLPTM [1.2K]2 years ago
3 0

90 miles and 180 minutes ?????

So basically, I'm pretty sure you have to multiply to get 180, but to get your answer first, I think you have to divide 90 by something to get 180 so it can equal together

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3 years ago
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3/4 a - q = k, solve for a
erastova [34]

Answer: a = 4k + 4q ÷ 3

Step-by-step explanation:

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if francisco drinks 2 2/3 ounces of water every 1/2 hours.How many ounces of water does francisco drink in one hour?
masha68 [24]

Answer:

5 1/3  Please mark me brainlliest

Step-by-step explanation:

2 2/3 every half-hour so for 1 full hour 2 2/3+2 2/3 = 5 1/3

8 0
3 years ago
A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as muc
Masteriza [31]

Let x represent amount invested in the higher-yielding account.

We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be 2x.

We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.

I=Prt, where,

I = Amount of interest,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

We are told that interest rates are 6% and 10%.

6\%=\frac{6}{100}=0.06

10\%=\frac{10}{100}=0.10

Amount of interest earned from lower-yielding account: 2x(0.06)=0.12x.

Amount of interest earned from higher-yielding account: x(0.10)=0.10x.

0.12x+0.10x=6600

Let us solve for x.

0.22x=6600

\frac{0.22x}{0.22}=\frac{6600}{0.22}

x=30,000

Therefore, the man invested $30,000 at 10%.

Amount invested in the lower-yielding account would be 2x\Rightarrow 2(30,000)=60,000.

Therefore, the man invested $60,000 at 6%.

8 0
2 years ago
A commercial aircraft gets the best fuel efficiency if it operates at a minimum altitude of 29,000 feet and a maximum altitude o
natita [175]

Answer:

x\geq 29,000  and  x\leq 41,000

Step-by-step explanation:

Let

x -----> the altitude of a commercial aircraft

we know that

The expression " A minimum altitude of 29,000 feet" is equal to

x\geq 29,000

All real numbers greater than or equal to 29,000 ft

The expression " A maximum altitude of 41,000 feet" is equal to

x\leq 41,000

All real numbers less than or equal to 41,000 ft

therefore

The compound inequality is equal to

x\geq 29,000  and  x\leq 41,000

All real numbers greater than or equal to 29,000 ft and less than or equal to 41,000 ft

The solution is the interval ------> [29,000,41,000]

5 0
3 years ago
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