Answer:
Therefore,
![r=\sqrt[3]{\frac{3V}{4\pi }}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D)
is the required r
Step-by-step explanation:
Given:
Volume of inside of the sphere is given as

where r is the radius of the sphere
To Find:
r =?
Solution:
We have
......Given
![3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}](https://tex.z-dn.net/?f=3%5Ctimes%20V%3D4%5Cpi%20r%5E%7B3%7D%20%5C%5C%5C%5C%5Ctherefore%20r%5E%7B3%7D%3D%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%20%5C%5C%5C%5C%5Ctherefore%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D%20%5Ctextrm%7Bwhich%20is%20the%20expression%20for%20r%7D)
Therefore,
![r=\sqrt[3]{\frac{3V}{4\pi }}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D)
is the required r
Answer:
Dimensions → (5 inches × 4 inches)
Step-by-step explanation:
Scale factor used for the drawing by Steffie = 
Since, scale factor = 
For Steffie,
Actual length of the crate = 
= 
= 45 inches
Actual width of the crate = 
= 36 inches
Since Brian used the scale factor = 
Length of the drawing = Actual length × Scale factor
= 45 × 
= 5 inches
Width of the drawing = Actual width × Scale factor
= 36 × 
= 4 inches
Therefore, dimensions of the drawing made by Brian are (5 inches × 4 inches)
Answer:
5.83 = CD
Step-by-step explanation:
We can use the pythagorean theorem to solve
The legs are the x and y distances
x = (1- -4) = 5 units and y = 3 units
a^2+ b^2 = c^2
5^2 + 3^2 = c^2
25+9 = c^2
34 = c^2
Taking the square root of each side
sqrt(34) = c which is the distance from C to D
5.830951895 = CD
5.83 = CD
D) horizontal stretch
hope it helps