Question

Given: 2x^2+3x-5, g(x)=x+9. Find: (fg)(3)

Answer 1

Answer:

264

Step-by-step explanation:

$f(x)=2x^2+3x-5$

$g(x)=x+9$

$(fg)(x)=f(x) \times g(x)$

$\implies (fg)(x)=(2x^2+3x-5)(x+9)$

$(fg)(3)=(2(3)^2+3(3)-5)(3+9)$

$\implies (fg)(3)=22 \times 12$

$\implies (fg)(3)=264$