Answer:
7.5 hours
Step-by-step explanation:
Using the variable 't' for time, you can set up an equation to find out how long it will take the truck to catch up to the bus. Since the bus is traveling at 60mph and the truck is traveling 1 2/3 times faster, we need to first find the rate of the truck:
1![\frac{2}{3}=\frac{5}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D%3D%5Cfrac%7B5%7D%7B3%7D)
![\frac{60}{1}*\frac{5}{3}=\frac{300}{3}=100mph](https://tex.z-dn.net/?f=%5Cfrac%7B60%7D%7B1%7D%2A%5Cfrac%7B5%7D%7B3%7D%3D%5Cfrac%7B300%7D%7B3%7D%3D100mph)
Using 't' and the knowledge that they will have traveled the same distance we the truck catches up to the bus and the fact that the truck left 3 hours later:
60t = 100(t - 3) or 60t = 100t - 300
Solve for 't': 60t - 100t = -300 or -40t = -300 so, t = 7.5 hours
Answer:
![2.06 \times 10^-^2 = 206](https://tex.z-dn.net/?f=2.06%20%5Ctimes%2010%5E-%5E2%20%3D%20206)
![1.88 \times 10^-^1 = 18.8](https://tex.z-dn.net/?f=1.88%20%5Ctimes%2010%5E-%5E1%20%3D%2018.8)
![206 \times 18.8 = 3,872.8](https://tex.z-dn.net/?f=206%20%5Ctimes%2018.8%20%3D%203%2C872.8)
![7.69 \times 10^-^2 = 769](https://tex.z-dn.net/?f=7.69%20%5Ctimes%2010%5E-%5E2%20%3D%20769)
![2.3 \times 10^-^5 = 230,000](https://tex.z-dn.net/?f=2.3%20%5Ctimes%2010%5E-%5E5%20%20%3D%20230%2C000)
![=\frac{769}{230000}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B769%7D%7B230000%7D)
= 0.00334
therefore,
3,872.80 > 0.00334
Step-by-step explanation:
Which statement is correct?
(2.06x102x1.88 x 10-1) <7.69x 10
2.3x10-5
(2.06 x 10-2)(1.88 x 10-1) 7.69x 10-
2.3x10-5
7.69 x 10"
(2.06 x 10-2x1.88x10-)>
2.3x10-5
(2.06x 10-2X(1.88x 10-1)-7.69x104
2.3x10-5
Given that;
![2.06 \times 10^-^2 = 206](https://tex.z-dn.net/?f=2.06%20%5Ctimes%2010%5E-%5E2%20%3D%20206)
![1.88 \times 10^-^1 = 18.8](https://tex.z-dn.net/?f=1.88%20%5Ctimes%2010%5E-%5E1%20%3D%2018.8)
![206 \times 18.8 = 3,872.8](https://tex.z-dn.net/?f=206%20%5Ctimes%2018.8%20%3D%203%2C872.8)
![7.69 \times 10^-^2 = 769](https://tex.z-dn.net/?f=7.69%20%5Ctimes%2010%5E-%5E2%20%3D%20769)
![2.3 \times 10^-^5 = 230,000](https://tex.z-dn.net/?f=2.3%20%5Ctimes%2010%5E-%5E5%20%20%3D%20230%2C000)
![=\frac{769}{230000}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B769%7D%7B230000%7D)
= 0.00334
therefore,
3,872.80 > 0.00334
The value would be 28,000*(1-0.0725)*(1-0.0725)*(1-0.0725)*(1-0.0725)*(1-0.0725)
which is 28,000*0,9275
![^{5}](https://tex.z-dn.net/?f=%20%5E%7B5%7D%20)
which equals 28,000*0.6863=$19,219
It has to be the first one