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julsineya [31]
2 years ago
10

How do i solve this and whats the answer v

Mathematics
1 answer:
emmainna [20.7K]2 years ago
4 0
Use Desmos it’ll explain all of that stuff
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Lisa is cutting a 14-inch piece of paper into 0.4-inch strips. How many strips of paper will she have when she is finished?
QveST [7]
35 pieces since 14/.4 is 35.
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3 years ago
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What is cos 16........
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The cos of 16 degrees is 0.96
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Please help me please i really need help please
ASHA 777 [7]

56.57.

Use Pythagorean theorem

7 0
3 years ago
(255)/(6)*(672)/(9)+(37)/(9) <br> How do you work this out step by step??
koban [17]
Step 1. Type it into a Google search box or calculator. (You need to use a calculator anyway.) The result is 3177 4/9.

If you're doing this according to the Order of Operations, you do the multiplication and division left to right. This means the first calculation you do is
  255/6 = 42.5
Next, you multiply by 672
  42.5*672 = 28560
Then divide by 9
  28560/9 = 3173 3/9

You continue by doing the division
  37/9 = 4 1/9

And finish by adding the two results
  3173 3/9 + 4 1/9 = 3174 4/9

_____
If you're doing this by hand, you can recognize the first term as the product of two fractions, so is the product of numerators divided by the product of denominators.
  (255*672)/(6*9)
Using your knowledge of divisibility rules, you can do the division 672/6 to simplify this to
  (255*112)/9
Now, the first term and the second term have the same denominator, so you can add the numerators before you do the division.
  (255*112 + 37)/9 = (28560 + 37)/9 = 28597/9
You end up having to do only two simple divisions, rather than 3 of them.
  28597/9 = 3177 4/9

7 0
3 years ago
What is the sum of the arithmetic sequence 3, 9, 15…, If there are 34 terms?
snow_tiger [21]

Answer:

first we find the common difference.....do this by subtracting the first term from the second term. (9 - 3 = 6)...so basically, ur adding 6 to every number to find the next number.

we will be using 2 formulas....first, we need to find the 34th term (because we need this term for the sum formula)

an = a1 + (n-1) * d

n = the term we want to find = 34

a1 = first term = 3

d = common difference = 6

now we sub

a34 = 3 + (34-1) * 6

a34 = 3 + (33 * 6)

a34 = 3 + 198

a34 = 201

now we use the sum formula

Sn = (n (a1 + an)) / 2

S34 = (34(3 + 201))/2

s34 = (34(204)) / 2

s34 = 6936/2

s34 = 3468 <=== the sum of the first 34 terms:

6 0
3 years ago
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