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meriva
2 years ago
8

You\:are\:buying\:the\:hamburgers\:and\:chicken\:for\:a\:party.\:The\:hamburgers\:cost\:2.75\:\:per\:pound\:and\:the\:chicken\:i

s\:3.50\:per\:pound.\:If\:you\:have\:75\:to\:spend,\:write\:and\:solve\:a\:linear\:equation\:to\:find\:out\:how\:many\:pounds\:of\:chicken\:you\:can\:afford\:if\:you\:buy\:12\:pounds\:of\:hamburgers.
Mathematics
1 answer:
atroni [7]2 years ago
5 0

Answer:

can you type it without doing the /:

Step-by-step explanation:

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lord [1]

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The answer is 600-p/24

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Read 2 more answers
One ordered pair $(a,b)$ satisfies the two equations $ab^4 = 12$ and $a^5 b^5 = 7776$. what is the value of $a$ in this ordered
LenaWriter [7]
This is the concept of algebra, given that ab^4=12 and a^5b^5=7776, the value if a will be found as follows:
ab^4=12
a=12/b^4
also;
a^5=7776/b^5
thus;
a=(7776/b^5)^(1/5)
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dividing both sides by b we get:
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multiplying both sides by b^3 we get
6b^3=12
b^3=2
hence;
b=2^(1/3)



8 0
3 years ago
How do you do this problem 1/4 +4x/5=11/20?
Nutka1998 [239]
\frac{1}{4}+\frac{4}{5}x=\frac{11}{20}\\\\\frac{4}{5}x=\frac{11}{20}-\frac{1}{4}\\\\\frac{4}{5}x=\frac{11}{20}-\frac{5}{20}\\\\\frac{4}{5}x=\frac{6}{20}\ \ \ \ \ \ \ |\cdot\frac{5}{4}\\\\x=\frac{30}{80}=\frac{3}{8}
8 0
2 years ago
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