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3 years ago

Simplify the expression by combining like terms.

Mathematics

1 answer:

bekas [8.4K]3 years ago

3 0

Answer:
1.9x+3.7
Explanation:
3.6x + (-1.7x)= 1.9x
5.9 - 2.2= 3.7

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A test is worth 50 points. Multiple-choice questions are worth 1 point, and short-answer questions are worth 3 points. If the te

dezoksy [38]

Use the following formula to find the answer to this question:

S * Q + M * Q = P

Representations:

S = The amount of points for short-answer questions.

M = The amount of points for multiple-choice questions.

Q = Number of questions for each of the type of questions that add up to the total number of questions on the test (20 questions).

P = Total points on the test.

Since there is a total of 50 points on the 20 question test, you would need to divide up the amount of questions there are for each of the type there are on the test, short-answer, and multiple-choice.

3 * Q + 1 * Q = P

Now find how many of the type of questions there are out of 20 questions on the test that would add up to the total number of points on the test.

3 * Q + 1 * Q = 50

(15 + 5 = 20 questions on the test, 15 and 5 can be used for the number of questions for each type of question on the test).

3 * 15 + 1 * 5 = 50

45 + 5 = 50

50 = 50

So, your total number of multiple choice questions are: 5.
And, your total number of short answer questions are: 15.

I would go with D. for your answer. I may be wrong.

I hope this helps. 

~ Notorious Sovereign

5 0

3 years ago

(06.04 MC)

Andru [333]

$\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}$

◉ $\large\bm{ -4}$

$\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}$

Before performing any calculation it's good to recall a few properties of integrals:

$\small\longrightarrow \sf{\int_{a}^b(nf(x) + m)dx = n \int^b _{a}f(x)dx + \int_{a}^bmdx}$

$\small\sf{\longrightarrow If \: a \angle c \angle b \Longrightarrow \int^{b} _a f(x)dx= \int^c _a f(x)dx+ \int^{b} _c f(x)dx }$

So we apply the first property in the first expression given by the question:

$\small \sf{\longrightarrow\int ^3_{-2} [2f(x) +2]dx= 2 \int ^3 _{-2} f(x) dx+ \int f^3 _{2} 2dx=18}$

And we solve the second integral:

$\small\sf{\longrightarrow2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot(3 - ( - 2)) }$

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} 2dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot5 = 2 \int^3_{-2} f(x)dx10 = }$

Then we take the last equation and we subtract 10 from both sides:

$\sf{{\longrightarrow 2 \int ^3_{-2} f(x)dx} + 10 - 10 = 18 - 10}$

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx = 8}$

And we divide both sides by 2:

$\small\longrightarrow \sf{\dfrac{2 { \int}^{3} _{2} }{2} = \dfrac{8}{2} }$

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx=4}$

Then we apply the second property to this integral:

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 4}$

Then we use the other equality in the question and we get:

$\small\sf{\longrightarrow 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx = 8 + 2 \int ^3_{-2} f(x)dx = 4}$

$\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =4}$

We substract 8 from both sides:

$\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx -8=4}$

• $\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =-4}$

7 0

1 year ago

B) Simplify 9y - 6y + y

julsineya [31]

Answer:

The answer is 4y

Step-by-step explanation:

Simplify the expression.

Hoped this helped!

Could I perhaps get brainly?

8 0

2 years ago

Read 2 more answers

X2 +8x+16=0 in factoring algorithm

Setler79 [48]

Answer:

(x+4)^2 =0

Step-by-step explanation:

x2 +8x+16=0

What 2 numbers multiply to 16 and add to 8

4*4 = 16

4+4 =8

(x+4) (x+4) =0

(x+4)^2 =0

4 0

2 years ago

Sophie says that if the interior angle of a triangle is 65 degrees and the exterior one is 295 degrees. Comment on her thinking

Yuri [45]

Sophie is correct because 295 + 65 = 360 and 360 is the # of degrees in a full circle

5 0

2 years ago