Answer:
<em>x = 1</em>
This is the equation that I interpreted:
6/(x) - 3 = 3/(x)
I have never worked with determining extraneous equations before, so I cannot answer the second part.
Answer:
Your equation is 
Step-by-step explanation:
Well, the center origin of the circle is given (h,k) = (1,-1).
We have to find our radius as they gave us a point. from origin to the edge of the circle.
Using the formula: (x - h)^2 + (y - k)^2 = r^2
Plug in our (h,k) = (1,-1) and (x,y) = (0.5,-1) to solve for radius.
(x - h)^2 + (y - k)^2 = r^2
(0.5 - (1))^2 + (-1 - (-1))^2 = r^2
(-0.5)^2 + (0)^2 = r^2
1/4= r^2
r^2 = 1/4
r = 1/2
Answer:
The answer is 2.5 or 5/2 as a fraction.
Step-by-step explanation:
P.S Can I have brainliest?
Answer:

Step-by-step explanation:
Slope Formula: 
Simply plug in 2 coordinates into the slope formula to find slope <em>m</em>:



Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π → C = π - (A + B)
→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))
→ sin C = sin (A + B) cos C = - cos(A + B)
Use the following Sum to Product Identity:
sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]
cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]
Use the following Double Angle Identity:
sin 2A = 2 sin A · cos A
<u>Proof LHS → RHS</u>
LHS: (sin 2A + sin 2B) + sin 2C




![\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]](https://tex.z-dn.net/?f=%5Ctext%7BFactor%3A%7D%5Cqquad%20%5Cqquad%20%5Cqquad%202%5Csin%20C%5Ccdot%20%5B%5Ccos%20%28A-B%29%2B%5Ccos%20%28A%2BB%29%5D)


LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C 