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Ksivusya [100]
2 years ago
15

Use ΔABC below to answer the question that follows:

Mathematics
2 answers:
Orlov [11]2 years ago
6 0

Two triangles can be similar by AAA,ASA ,SSS ,SAS property of similarity.

To prove triangles ABC  similar to DBE  we consider

Segments AC and DE are parallel.

AB is a transversal line passing AC and DE.

Angle B is congruent to itself due to the reflexive property.

The option which is not used to prove that ABC is similar to DBE is the first option :

The sum of angles A and B are supplementary to angle C.


Elza [17]2 years ago
4 0

Answer:


Step-by-step explanation:

To prove Δ ABC similar to ΔDBE  we can consider

Segments AC and DE are parallel.

⇒ DE intersects AB and BC in same ratio.

AB is a transversal line passing AC and DE.

⇒∠BAC=∠BDE [corresponding angles]

Angle B is congruent to itself due to the reflexive property.

All of them are telling a relation of parts of ΔABC to ΔDBE.

The only option which is not used to prove that ΔABC is similar to ΔDBE is the first option ,"The sum of angles A and B are supplementary to angle C".

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arsen [322]

Answer:

See below ~

Step-by-step explanation:

Given :

<u>QRSTU ~ FGCDE</u>

Finding the scale factor :

  • Take two corresponding sides in proportion
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Applying the scale factor to find the missing sides :

- FG :

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- CD :

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- EF :

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If the numerator and denominator of the fraction is increased by 2an1 respectively; it becomes3/4 if the numerator and the denom
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Answer:

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Step-by-step explanation:

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So, Fraction = \frac{x}{y}

Now we are given that numerator and denominator of the fraction is increased by 2 and 1 respectively. it becomes 3/4

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4x-3(2x-3)+5=0

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